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babunello [35]
3 years ago
8

Find the product of $$12\times5$$​

Mathematics
2 answers:
VashaNatasha [74]3 years ago
6 0

Answer:

60

Step-by-step explanation:

(I am a bit confused of the wording / layout, but I think this is what you need!)

Key notes:

- "the product of" means multiplication

12 * 5 = 60

valentinak56 [21]3 years ago
5 0

Answer:

60

Step-by-step explanation:

12x5=60

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Simplify the following expression:<br> Sqrt (-16) + sqrt(-25+5)
Studentka2010 [4]

Answer:

(4 + 2√5) i

Step-by-step explanation:

√(-16) + √(-25 + 5)

√(-16) + √(-20)

4i + 2i√5

(4 + 2√5) i

7 0
3 years ago
Can someone help with this?? :)))
Y_Kistochka [10]

Answer:

5.3

You split them up into smaller root numbers and add them together

6 0
2 years ago
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P(k)=a^k=2 3 4 find value of a that makes this is a valid probability distribution
Vesna [10]
Sounds like you're asked to find a such that

\displaystyle\sum_{k=2}^4\mathbb P(k)=\mathbb P(2)+\mathbb P(3)+\mathbb P(4)=1

In other words, find a that satisfies

a^2+a^3+a^4=1

We can factorize this as

a^4+a^3+a^2-1=a^3(a+1)+(a-1)(a+1)=(a+1)(a^3+a-1)=0

In order that \mathbb P(k) describes a probability distribution, require that \mathbb P(k)\ge0 for all k, which means we can ignore the possibility of a=-1.

Let a=y+\dfrac xy.

a^3+a-1=\left(y+\dfrac xy\right)^3+\left(y+\dfrac xy\right)-1=0
\left(y^3+3xy+\dfrac{3x^2}y+\dfrac{x^3}{y^3}\right)+\left(y+\dfrac xy\right)-1=0

Multiply both sides by y^3.

y^6+3xy^4+3x^2y^2+x^3+y^4+xy^2-y^3=0

We want to find x\neq0 that removes the quartic and quadratic terms from the equation, i.e.

\begin{cases}3x+1=0\\3x^2+x=0\end{cases}\implies x=-\dfrac13

so the cubic above transforms to

y^6-y^3-\dfrac1{27}=0

Substitute y^3=z and we get

z^2-z-\dfrac1{27}=0\implies z=\dfrac{9+\sqrt{93}}{18}
\implies y=\sqrt[3]{\dfrac{9+\sqrt{93}}{18}}
\implies a=\sqrt[3]{\dfrac{9+\sqrt{93}}{18}}-\dfrac13\sqrt[3]{\dfrac{18}{9+\sqrt{93}}}
6 0
3 years ago
Find the area of a circle, diameter measures 30 ft​
Furkat [3]

Answer:

The A≈706.86

Step-by-step explanation

A=πr2

d=2r

Solving for A

A=1

4πd2=1

4·π·302≈706.85835

Hope this helps : )

8 0
3 years ago
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A number greater than 2 and it has a 2 as a factor is the number prime or composite
GarryVolchara [31]

Answer:

Composite

Step-by-step explanation:

That number is composite. The definition of prime is a number whose two factors are one and itself. If it has two, it must be composite, because that is not one OR itself

7 0
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