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svetlana [45]
3 years ago
13

Alejandro needs to buy bird seed from the local pet store for his parrots. A

Mathematics
1 answer:
Gnesinka [82]3 years ago
7 0

First take note he only has $20 and the bag he must buy is $12.55. Also the loose seeds are $1.49 per pound.

To solve subtract 12.55 from 20

20-12.55=7.45

So after buying the 10 lb bag he has $7.45 left now divide that by 1.49

7.45/1.49=5

So after buying the 10 lb bag he can also buy 5 lb of the loose seeds!


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1 gallon of batter is poured equally into 4 bowls. How many gallons of batter are in each bowl?
yarga [219]

Answer:

1/4 of a gallon otherwise known as 1 quart.

Step-by-step explanation:

This is because you are spliting one thing into four parts so each bowl would have 1/4 of the gallon.

5 0
3 years ago
In 2010, the population of a city was 241,000. From 2010 to 2015, the population grew by 5%. From 2015 to 2020, it fell by 4%. T
lawyer [7]

Answer:

242, 900 people

Step-by-step explanation:

To begin, it says that the population grew by 5%.

(241000)(1.00 + 0.05) = <em>population of the city in 2015</em>

(241000)(1.05) = 253050

253050 is the population of the city in 2015. From 2015 to 2020 it fell four percent.

(253050)(1.00 - 0.04) = <em>population of the city in 2020</em>

(253050)(0.96) = 242928

242928 is the exact population of the city. However, it says to round to the nearest hundred. Since 28 is less than 50, then it would round down to 900.

Therefore, the answer would be 242, 900 people.

4 0
3 years ago
What are the x and y intercepts of 2x-3y=6?
Annette [7]
X=67/2
y=-67/3
x and y intercepts
8 0
3 years ago
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Find the length of side s. Round to the nearest tenth if needed.
Ilya [14]

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dunno

Step-by-step explanation:

4 0
3 years ago
the mgf of a random variable x is e^3(e^t-1). Find P[mean - standard deviation squared &lt; X &lt; 1/2( mean + standard deviatio
postnew [5]
The given MGF is that for a random variable following a Poisson distribution with parameter \lambda=3.

This means \mathbb E(X)=\mathbb V(X)=\lambda, and X has PMF

f_X(x)=\begin{cases}\dfrac{3^xe^{-3}}{x!}&\text{for }x\ge0\\0&\text{otherwise}\end{cases}

So, the desired probability is

\mathbb P\left(\lambda-\lambda^2

This is equivalent to

\displaystyle\sum_{x=0}^2\mathbb P(X=x)=\sum_{x=0}^2\frac{3^x}{x!e^3}=\frac{17}{2e^3}\approx0.4232
8 0
3 years ago
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