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faltersainse [42]
2 years ago
12

2-1/2 cups water minus 1-2/3 cups water =

Mathematics
1 answer:
weeeeeb [17]2 years ago
7 0

The difference between the mixed numbers is equal to 5/6.

<h3>How to perform the subtraction between the two mixed numbers?</h3>

A mixed number is a number that is written as a whole number plus an improper fraction, here we want to compute:

(2 + 1/2) - (1 + 2/3)

We can group the whole numbers and the fractions, so we get:

(2 - 1) + (1/2 - 2/3)

Now we can simplify this so we get:

(2 - 1) + (1/2 - 2/3)

= 1 + (3/6 - 4/6) = 1 - 1/6 = 6/6 - 1/6 = 5/6

We conclude that the difference between the mixed numbers is equal to 5/6.

If you want to learn more about mixed numbers:

brainly.com/question/1746829

#SPJ1

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Martin is an artist who molds plaster into unique shapes.
defon

Step-by-step explanation:

the volume of this object is the sum of the volume of the 2 blocks.

the large block is a cube of 4×4×4 = 64 ft³

the small block is 1×1×2 = 2 ft³

so, in total, he can fit 64+2 = 66 ft³ of plaster into the mold.

8 0
2 years ago
What 9/2-11/4 plz help i only have 10 mins till due
svp [43]

Answer:

7/4

Step-by-step explanation:

9/2 - 11/4

Get a common denominator of 4

9/2 *2/2  - 11/4

18/4 - 11/4

7/4

8 0
2 years ago
Read 2 more answers
4. Given the diagram below what is the length of RS or the distance across a body of water?
kaheart [24]

Answer:

The answer is about 97.

5 0
2 years ago
2 women and 7 girls can do a peice of work in 4 days.4 women and 4 girls can do the same work in 3 days. How long would it take
svetlana [45]

Answer:

x: work a woman can do in 1 day

y: work a girl can do in 1  day

Then

2x + 7y =1/4

4x + 4y =1/3

4x + 14y =2/4 (1)

4x + 4y  =1/3 (2)

=> Let (1) - (2), 10y =2/4-1/3 <=>10y = 1/6 <=> y = 1/(6x10) = 1/60 (work)

=> From (2),4x = 1/3 - 4x1/60 => 4x = 16/60 => x = 4/60 (work)

=> 1 day, a woman and a girl can do: 1/60+4/60 = 5/60 =1/12 (work)

Then, the day required for a woman and a girl to complete work: 12 days

3 0
3 years ago
<img src="https://tex.z-dn.net/?f=5%20%7Bx%7D%5E3%20-%2020%20%7Bx%7D%5E%7B2%7D%20%3D%200" id="TexFormula1" title="5 {x}^3 - 20 {
adell [148]

5x^{2}  \times (x - 4) = 0 \\ x^{2} \times (x - 4) = 0 \\  {x}^{2} = 0 \: x = 0 \\ x - 4 = 0 \: x = 4
7 0
3 years ago
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