

- <u>We </u><u>have </u><u>given </u><u>a</u><u> </u><u>right</u><u> </u><u>angled </u><u>triangle </u><u>whose </u><u>values </u><u>are </u><u>m</u><u>, </u><u> </u><u>n </u><u>and </u><u>2</u><u> </u>

- <u>We </u><u>have </u><u>to </u><u>find </u><u>the </u><u>value </u><u>of </u><u>m </u><u>and </u><u>n</u>

<u>In </u><u>the </u><u>given </u><u>right </u><u>angled </u><u>triangle</u><u>, </u><u>we </u><u>have </u>
- Perpendicular height = n units
- Base = 2 units
- Hypotenuse = m units
<u>Now</u><u>, </u><u> </u><u>By </u><u>using </u><u>trigonometric </u><u>ratios </u>



<u>According </u><u>to </u><u>the </u><u>question </u><u>:</u><u>-</u>



- <u>We </u><u>know </u><u>that </u><u>,</u><u> </u><u>Sum </u><u>of </u><u>Angles</u><u> </u><u>of </u><u>triangle </u><u>is </u><u>1</u><u>8</u><u>0</u><u>°</u><u> </u><u>.</u>
<u>Therefore</u><u>, </u>
Let the unknown angle be x



<u>Now</u><u>, </u>





Thus, The value of m = 2√2 and n = 2

Let us consider the distance between kensington and greenwich be x
since the given figure is a right angled triangle,we use pythagoras theorem to find the answer
so by pythagoras theorem
x^2= 20^2+40^2
x^2=400+1600
x^2=2000
x=root of 2000=20root 5mi
answer is option (b)
Answer:
this triangle is an acute triangle
Answer:
Step-by-step explanation:
domain: x>5
range: y > 0
5,28-(x4-3,,,,,,,,,,,,,,,,,