George wanted to measure the angle of a water slide at the lake. He used a sheet of folded paper that formed a 20° angle. He mea
1 answer:
The angle of the water slide is 60 degrees.
The equation that models his work is 3 × 20 = 60 degrees.
<h3>How to find the sum of angles of a figure/object?</h3>
He wants to measure the angle of a water slide at the lake.
He used a sheet of folded paper that formed 20 degrees to measure the angle of the the water slide at the lake.
He noticed three folded paper angle fits in the angle made by the slide and the ground.
Since each angle is equals to 20 degrees, and the three fits into the angle made by the slide and the ground, the angle of the water slide is as follows:
20 × 3 = 60 degrees
learn more on angles here: brainly.com/question/16746032
You might be interested in
Answer:
(a) The correct answer is P (CBM) = 0.79.
(b) The probability of selecting an American female who is not red-green color-blind is 0.996.
(c) The probability that neither are red-green color-blind is 0.9263.
(d) The probability that at least one of them is red-green color-blind is 0.0737.
Step-by-step explanation:
The variables CBM and CBW are denoted as the events that an American man or an American woman is colorblind, respectively.
It is provided that 79% of men and 0.4% of women are colorblind, i.e.
P (CBM) = 0.79
P (CBW) = 0.004
(a)
The probability of selecting an American male who is red-green color-blind is, 0.79.
Thus, the correct answer is P (CBM) = 0.79.
(b)
The probability of the complement of an event is the probability of that event not happening.
Then,
P(not CBW) = 1 - P(CBW)
= 1 - 0.004
= 0.996.
Thus, the probability of selecting an American female who is not red-green color-blind is 0.996.
(c)
The probability the woman is not colorblind is 0.996.
The probability that the man is not color- blind is,
P(not CBM) = 1 - P(CBM)
= 1 - 0.004
= 0.93.
The man and woman are selected independently.
Compute the probability that neither are red-green color-blind as follows:
Thus, the probability that neither are red-green color-blind is 0.9263.
(d)
It is provided that a one man and one woman are selected at random.
The event that “At least one is colorblind” is the complement of part (d) that “Neither is Colorblind.”
Compute the probability that at least one of them is red-green color-blind as follows:
Thus, the probability that at least one of them is red-green color-blind is 0.0737.