1 year ago

(x² + 6x-5) + (x²-8x-4)

Mathematics

1 answer:

leonid [27]1 year ago

8 0

Answer: 2x^2-2x-9

Step-by-step explanation:

subtract the numbers

x^2 + 6x-5+x^2-8x-4

X^2+6x-9+x^2-8x

then your gonna combine like terms

x^2+6x-9=x^2-8x

2x^2+6x-9-8x

combine like terms

2x^2+6x-9-8x

2x^2-2x-9

solution

2x^2-2x-9

You might be interested in

I catfished someone and I was being so nice I don’t think I’ve ever been that nice to someone the point is that imma Kermit (mem

Katyanochek1 [597]

Omg don’t catfish it’s so damaging to your own self confidence!

4 0

3 years ago

Select all the partial products for

babymother [125]

Answer:

ok639010 is the answer of the day when I am in the toilet

8 0

3 years ago

Read 2 more answers

What is the cube root of -729a^9b^6? -9a^3b^2 -9a^2b^ -8a^3b^2 -8a^2b^3

timurjin [86]

Answer:

$= 9a^3b^2$

Step-by-step explanation:

$\sqrt[3]{-729a^9b^6} =$

$= ((-9)^3a^9b^6)^{\frac{1}{3}$

$= (-9)^{3 \times \frac{1}{3}} \times a^{9 \times \frac{1}{3}} \times b^{6 \times \frac{1}{3}}$

$= (-9)^{1} \times a^{3} \times b^{2}$

$= -9a^3b^2$

7 0

1 year ago

Verify that [tan(theta) + cot(theta)]^2 = sec^2(theta) + csc^2(theta)

Wittaler [7]

(tanθ + cotθ)² = sec²θ + csc²θ

Expand left side: tan²θ + 2tanθcotθ + cot²θ

Evaluate middle term: 2tanθcotθ = $2*\frac{sin\theta}{cos\theta}*\frac{cos\theta}{sin\theta}$ = 2

⇒ tan²θ + 2+ cot²θ

= tan²θ + 1 + 1 + cot²θ

Apply trig identity: tan²θ + 1 = sec²θ

⇒ sec²θ + 1 + cot²θ

Apply trig identity: 1 + cot²θ = csc²θ

⇒ sec²θ + csc²θ

Left side equals Right side so equation is verified

7 0

2 years ago

PLS Write a real world problem for the inequality 8-2x≤5.

Hatshy [7]

Step-by-step explanation:

8-2x< 5
-2x<5-8
x< -3/-2
x<1.5

hope it helps.

3 0

2 years ago