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Dahasolnce [82]
2 years ago
6

Hund's rule states that when a sublevel contains several orbitals of equal energy, electron(s) must be placed in each orbital be

fore electrons are?
Chemistry
1 answer:
Thepotemich [5.8K]2 years ago
7 0

Hund's rule states that when a sublevel contains several orbitals of equal energy, electron(s) must be placed in each orbital before electrons are <u>paired.</u>

<u />

According to Hund's rule, each orbital within a sublevel is always singly occupied before it becomes double occupied. Every electron in solely filled orbitals possesses the same spin.

Only when every orbital in a sublevel has one electron would electrons pair up inside an orbital. They are all the same spin whenever a single electron is present in many orbitals within the same sublevel.

Therefore, Hund's rule states that when a sublevel contains several orbitals of equal energy, electron must be placed in each orbital before electrons are <u>paired.</u>

To know more about Hund's rule states

brainly.com/question/12646067

#SPJ4

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In the citric acid cycle, ATP molecules are produced by _____. In the citric acid cycle, ATP molecules are produced by _____. su
monitta

Answer:

substrate-level phosphorylation

Explanation:

Substrate-level phosphorylation is the metabolic reaction which results in formation of energy currency molecules, ATP or GTP by direct transfer of a phosphoryl group to the ADP or GDP from the another phosphorylated compound.

<u>In citric acid cycle, Succinyl-CoA in the presence of succinyl-CoA synthase is converted to succinate. Condensation reaction (Substrate-level phosphorylation) of GDP and Pi takes place which results in the formation of GTP.</u>

3 0
3 years ago
A local barista serves coffee at 85°C. You add ice to the coffee to cool it to 55°C. Assume that an ice cube is 24 g and -18.5°C
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3 0
3 years ago
B) Quelle est la masse de tétraoxyde de trifer (Fe3O4) produite si 3,60 moles de trioxyde de
hram777 [196]

Answer:

626,4 g de Fe₃O₄

Explanation:

Nous commencerons par écrire l'équation équilibrée de la réaction entre le fer (Fe) et le trioxyde d'aluminium. Ceci est donné ci-dessous:

9Fe + 4Al₂O₃ -> 3Fe₃O₄ + 8Al

De l'équation équilibrée ci-dessus,

4 moles d'Al₂O₃ ont réagi pour produire 3 moles de Fe₃O₄.

Par conséquent, 3,6 moles d'Al₂O₃ réagiront pour produire = (3,6 × 3) / 4 = 2,7 moles de Fe₃O₄

Ainsi, 2,7 moles de Fe₃O₄ sont produites à partir de la réaction.

Enfin, nous déterminerons la masse massique de Fe₃O₄ produite par la réaction. Ceci peut être obtenu comme suit:

Mole de Fe₃O₄ = 2,7 moles

Masse molaire de Fe₃O₄ = (3 × 56) + (4 × 16)

= 168 + 64

= 232 g / mol

Masse de Fe₃O₄ =?

Mole = masse / masse molaire

2,7 = Masse de Fe₃O₄ / 232

Croiser multiplier

Masse de Fe₃O₄ = 2,7 × 232

Masse de Fe₃O₄ = 626,4 g

Par conséquent, 626,4 g de Fe₃O₄ sont produits à partir de la réaction

7 0
3 years ago
If an atom has sp3d2 hybridization in a molecule:
never [62]

Answer:

a. the maximum number of σ bonds that the atom can form is 4

b. the maximum number of p-p bonds that the atom can form is 2

Explanation:

Hybridization is the mixing of at least two nonequivalent orbitals, in this case, we have the mixing of one <em>s, 3 p </em> and <em> 2 d </em> orbitals. In hybridization the number of hybrid orbitals generated  is equal to the number of pure atomic orbital, so we have 6 hybrid orbital.

The shape of this hybrid orbital is octahedral (look the attached image) , it has 4 orbital located in the plane and 2 orbital perpendicular to it.

This shape allows the formation of maximum 4 σ bond, because σ bonds are formed by orbitals overlapping end to end.

And maximum 2 p-p bonds, because p-p bonds are formed by sideways overlapping orbitals. The atom can form one with each one of the orbitals located perpendicular to the plane.

4 0
3 years ago
Read 2 more answers
Using the molarity equation, calculate how many grams of salt you need in order to make 80ml of a 2M solution (MW = 58.44g/mole)
ollegr [7]

Answer:

9.35g

Explanation:

The molarity equation establishes that:

\textrm{molarity}=\frac{\textrm{moles  of solute}}{\textrm{liters of solution}}

So, we have information about molarity (2M) and volume (80 ml=0.08 l), with that, we can find the moles of solute:

\textrm{moles of solute}=\textrm{molarity}*\textrm{liters of solution}

\textrm{moles of solute}= 0.08 \textrm{ l} *2\textrm{ M} = 0.16 \textrm{ mol}

The  mathematical equation that establishes the relationship between molar weight, mass and moles is:

\textrm{molar weight}= \frac{\textrm{mass}}{\textrm{moles}}

\textrm{MW}= \frac{\textrm{m}}{\textrm{n}}

We have MW (58.44g/mole) and n (0.16 mol), and we need to find m (grams of salt needed) to solve the problem:

\textrm{m} = \textrm{MW * n}= 58.44\frac{\textrm{g}}{\textrm{mol}} * 0.16 \textrm{ mol} = 9.35 \textrm{ g}

8 0
4 years ago
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