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valentinak56 [21]
3 years ago
8

The initiator trna attaches at the ribosome's _____ site.

Chemistry
1 answer:
boyakko [2]3 years ago
5 0
It is in the P-site of the ribosome wherein the initiator TRNA is attached. In addition, it is the area wherein the t-RNA would be bound for the second time inside the ribosome. Another name for the P-site is peptidyl. On the other hand, other ribosome sites include the A-site and the E-site. 
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Drag the handle on the left and adjust the length of the box to 5 nm. (Because no other dimensions of the box change, its length
kvv77 [185]

Answer:

Length (nm) Pressure (atm)

5.0 11.7

6.0 9.8

7.0 8.4

8.0 7.2

9.0 6.6

10.0 5.8

Explanation:

This is also PLATOS answer!!

7 0
3 years ago
A reversible reaction is a reaction that takes place in the____1____ . If the reaction were to_____2____, the rate of the forwar
klemol [59]

Answer : The correct option for blank 1 is, Forward and Backward direction .

The correct option for blank 2 is, Reach equilibrium .

Explanation :

  • Reversible reaction : It is a reaction in which two or more reactants react together to give products and these products react with other product to form reactants.

It occurs in both the directions at the same time, forward and backward direction.

  • Irreversible reaction : It is a reaction in which reactants react together to give a product but it can not revert back into the reactants.

It occurs in forward direction only.

  • Equilibrium reaction : It is a reaction in which the rate of forward reaction is equal to the rate of backward reaction.
  • Completion reaction : It is a reaction in which the reactants react together to give products. when the reaction goes to completion theta means all the reactants are used up and you have only products in the reaction.
8 0
4 years ago
1 mole of hcl(g) has a greater entropy than 1 mole of hbr(g). true or false
yan [13]
False. Due to:
Entropy increases with molecular size (mass of compound)
HBr has greater molecular size (molar mass) than HCl
The value of standard entropy of HCl(g) is 187 joules/ kelvin 
The value of standard entropy of HBr(g) is 199 joules / kelvin
7 0
3 years ago
Explain the difference between cocl2 6h2o and anhydrous cobalt chloride
lana66690 [7]
<span>Colbat (ii) which is a compound birth out of the combination of chlorine and colbat to form Cocl2.6h2o has water in it as we can see from it's chemical it's hexahydrate Anhydrous cobalt chloride as the word anhydrous clearly states , does not have water in</span>
8 0
4 years ago
How many milliliters of 0.100 M NaOH are required to neutralize the following solutions?
gulaghasi [49]

Answers:

  • a.) 10.0 mL of 0.0500 M HCl: 5.00 ml
  • b.) 25.0 mL of 0.126 M HNO₃: 31.5 ml
  • c.) 50.0 mL of 0.215 M H₂SO4: 215. ml

Explanation:

All the reactions are the neutralization of strong acids with the same strong base.

At the neutralization point you have:

  • number of equivalents of the base = number of equivalent of the acid

And the number of equivalents (#EQ) may be calculated using the normality (N) concentration and the volume (V)

  • # EQ = N × V

Then, at the neutralization point:

  • # EQ acid = N acid × V acid

  • # EQ base = N base × V base

  • # EQ acid = # EQ base

  • N acid × V acid = N base × V base

Also, you can use the formula that relates normality with molarity

  • N = M × number of hydrogen or hydroxide ions

<u>a.) 10.0 mL of 0.0500 M HCl</u>

  • The number of hydrogen ions for HCl is 1 and the number of hydroxide ions for NaOH is 1.

  • 10.0 ml × 0.0500 M × 1 = V base × 0.100 M × 1

         ⇒ V base = 10.0 ml ×0.0500 M / 0.100 M = 5.00 ml

<u>b.) 25.0 mL of 0.126 M HNO₃</u>

  • The number of hydrogen ions for HNO₃ is 1 and the number of hydroxide ions for NaOH  is 1.

  • 25.0 ml × 0.126 M × 1 = V base × 0.100 M × 1

         ⇒ V base = 25.0 ml ×0.126 M / 0.100 M = 31.5 ml

<u>c.) 50.0 mL of 0.215 M H₂SO4</u>

  • The number of hydrogen ions for H₂SO4 is 2 and the number of hydroxide ions for NaOH  is 1.

  • 50.0 ml × 0.215 M × 2 = V base × 0.100 M × 1

         ⇒ V base = 50.0 ml ×0.215 M × 2 / 0.100 M = 215. ml

7 0
3 years ago
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