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vichka [17]
1 year ago
12

At Johnson's Pharmacy, tissue boxes can be purchased as single boxes or in packs of three boxes. During January, Johnson's sells

a
Cotal of 379 boxes of tissues, 68 as single boxes, and the rest in three-packs. Which equation shows the number of tissue three-
packs, p, Johnson's sold in January?
Mathematics
1 answer:
Katena32 [7]1 year ago
4 0

Answer:

379-68=p

Step-by-step explanation:

379 is the total number of tissues. If you take away the single pack tissues then you will have the amount of three pack tissues

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The surface area of a rectangular prism is 2,280 square feet. If the width and height are 20 and 15 feet, the length of the pris
kolbaska11 [484]

Answer:

The statement is trrue.

Step-by-step explanation:

Given that,

The surface area of a rectangular prism = 2,280 square feet

Width, b =20 feet

Height, h = 15 feet

The formula for the surface area of a rectangular prism is given by :

A=2(lb+bh+hl)

Where

l is the length of the prism

Substitute all the values,

A=2(lb+bh+hl)\\\\2,280=2(20l+20\times 15+15l)\\\\1140=(20l+20\times 15+15l)\\\\1140=35l+300\\\\1140-300=35l\\\\35l=840\\\\l=24\ feet

So, the length of the prism is equal to 24 feet.

6 0
3 years ago
NEED HELP WITH THESE
faltersainse [42]

Step-by-step explanation:

1 .f(x)=x^{2}-x+1

   f(-1)= (-1)-(-1)+1

   f(-1)= 1+1+1

      = 3

3.f(x)=x^{2}-x+1

 f( 1)=(1)-1+1

  f( 1)=1-1+1

        =1

5. f(x)=x^{2}-x+1

    f(3)=(3)^{2}-3+1

         = 9-3+1

          =7

2. g(x) = 5 - 3x

 g( -8)=5-3(-8)

g( -8)=5+24

        =29

4.g(x) = 5 - 3x

g(5)=5-3(5)

 g(5)=5-15

       =-10

6.g(x) = 5 - 3x

   g(-3)=5-3(-3)

 g(-3)=5+9

         =14

3 0
3 years ago
For the function y=3x2: (a) Find the average rate of change of y with respect to x over the interval [3,6]. (b) Find the instant
nirvana33 [79]

Answer:

The instantaneous rate of change of y with respect to x at the value x = 3 is 18.

Step-by-step explanation:

a) Geometrically speaking, the average rate of change of y with respect to x over the interval by definition of secant line:

r = \frac{y(b) -y(a)}{b-a} (1)

Where:

a, b - Lower and upper bounds of the interval.

y(a), y(b) - Function exaluated at lower and upper bounds of the interval.

If we know that y = 3\cdot x^{2}, a = 3 and b = 6, then the average rate of change of y with respect to x over the interval is:

r = \frac{3\cdot (6)^{2}-3\cdot (3)^{2}}{6-3}

r = 27

The average rate of change of y with respect to x over the interval [3,6] is 27.

b) The instantaneous rate of change can be determined by the following definition:

y' =  \lim_{h \to 0}\frac{y(x+h)-y(x)}{h} (2)

Where:

h - Change rate.

y(x), y(x+h) - Function evaluated at x and x+h.

If we know that x = 3 and y = 3\cdot x^{2}, then the instantaneous rate of change of y with respect to x is:

y' =  \lim_{h \to 0} \frac{3\cdot (x+h)^{2}-3\cdot x^{2}}{h}

y' =  3\cdot \lim_{h \to 0} \frac{(x+h)^{2}-x^{2}}{h}

y' = 3\cdot  \lim_{h \to 0} \frac{2\cdot h\cdot x +h^{2}}{h}

y' = 6\cdot  \lim_{h \to 0} x +3\cdot  \lim_{h \to 0} h

y' = 6\cdot x

y' = 6\cdot (3)

y' = 18

The instantaneous rate of change of y with respect to x at the value x = 3 is 18.

5 0
3 years ago
When Adam verified his answer, it didn't work What
Elenna [48]

Answer:

(D) he should have found that there are no solutions because the statement is false

5 0
3 years ago
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Write 7x10^-8 in standard form
attashe74 [19]

Answer:

The answer would be 0.00000007

6 0
3 years ago
Read 2 more answers
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