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amm1812
4 years ago
12

Check all the ordered pairs that satisfy the equation below. Y=6x

Mathematics
1 answer:
slava [35]4 years ago
3 0
If \frac{y}{x} = 6, then any ordered pair would satisfy the equation.
Since we're not given the ordered pairs, then this is the only information I can give to you.
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How to find sides of gon with meaure of each angle exterior?
MrMuchimi
All exterior angles of n-gon always add up to 360°

To find the number of sides:

\text {Number of sides = }  \dfrac{360}{\text {size of one exterior angle}}
8 0
4 years ago
Geometry work how do I find the distance in miles
puteri [66]
I think division. I don’t know, I might be wrong. ‍♀️
4 0
4 years ago
If she chooses the 8-inch tiles, she will need a quarter as many tiles as she would with 2-inch tiles.
denis23 [38]

In the above word problem, If she chooses the 8-inch tiles, she will need a quarter as many tiles as she would with 2-inch tiles, Quarter 8-inch tiles will cover the same area as one 2-inches.

<h3>What is the justification for the above?</h3>

Note that the area of the one 2-inch tiles is given as:

A1 = 4in²

The area of the quarter 8-inch tiles is:

A2 = 1/4 x 8 x 8

A2 = 16inch²

Divide both areas

A2/A1= 16/4

= 4

This implies she'll need four 2-inch tiles to cover the same amount of space as a quarter 8-inch tile.

Learn more about word problems:
brainly.com/question/13818690
#SPJ4

Full Question:

A homeowner is deciding on the size of tiles to use to fully tile a rectangular wall in her bathroom that is 80 inches by 40 inches. The tiles are squares and come in three side lengths: 8 inches, 4 inches, and 2 inches. State if you agree with each statement about the tiles. Explain your reasoning.

If she chooses the 8-inch tiles, she will need a quarter as many tiles as she would with 2-inch tiles,

8 0
2 years ago
X2 −2x + y2 − 6y = 26 what is the radius
Thepotemich [5.8K]
r > 0\\\\(x-a)^2+(y-b)^2=r^2\\\\x^2-2x+y^2-6y=26\\\\ (x-1)^2-1+(y-3)^2-9=26\\\\ (x-1)^2+(y-3)^2-10=26 \ |+10\\\\(x-1)^2+(y-3)^2=36\\\\ r^2=36 \ \Rightarrow \ r=6
4 0
3 years ago
Wayne has a recipe on a 3 inch by 5 inch index card that he wants to    enlarge to 15 inches long. How wide will the enlargement
SVETLANKA909090 [29]
I'm not completely sure which way they would like for you to do it
but anyways

3 to 15 is a times 5
so 5 times 5 is 25
so a possible width can be 25
as in 15 by 25

or

5 to 15 is times 3
so 3 times 3 is 9
so a possible width can be 9
as in 15 by 9

I personally think 25 inches wide would be the better answer
5 0
4 years ago
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