Check whether it is possible to have a triangle with the given side lengths for example 7,9,13 then add any two sides and see if it is greater than the other side. Example the sum of 7 and 9 is 16 and 16 is greater than 13
Answer:
a(n) = a(1) + 6(n -1)
Step-by-step explanation:
The common difference here is 6. 1 + 6 = 7; 13 + 6 = 19; and so on.
Thus, the function in question is a(n) = a(1) + 6(n -1).
<h3>
Answer: Choice C. (2x - 6i)(x + 3i)</h3>
Work Shown:
2x^2 + 18
2(x^2 + 9)
2(x - 3i)(x + 3i) .... see note below
(2x - 6i)(x + 3i)
Note: I used the rule that a^2 + b^2 = (a - bi)(a + bi). I recommend FOILing out the right hand side to confirm the equation is true. You'll use the idea that i^2 = -1.
-12x - 9 = -6y
-12x + 6y -9 = 0
-12x + 6y = 9 is the answer
Answer:
The sets of values that correctly completes the t-chart are:
7, -1, 7
Hence, option B is true.
Step-by-step explanation:
Given the equation
y = 2x² - 1
FOR x = -2
substitute x = -2 in the equation
y = 2x² - 1
y = 2(-2)² - 1
y = 8 - 1
y = 7
FOR x = 0
substitute x = 0 in the equation
y = 2x² - 1
y = 2(0)² - 1
y = -1
FOR x = 2
substitute x = 2 in the equation
y = 2x² - 1
y = 2(2)² - 1
y = 8 - 1
y = 7
Thus, the t-chart becomes:
x y
-2 7
0 -1
2 7
Thus, the sets of values that correctly completes the t-chart are:
7, -1, 7
Hence, option B is true.
