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irina [24]
1 year ago
14

Find the equation of the circle center (-3, 4) with radius 7 units.

Mathematics
1 answer:
NNADVOKAT [17]1 year ago
6 0

The equation of the circle with center (-3, 4) and radius 7 units is ( x + 3 )² + ( y - 4 )² = 49.

<h3>What is the equation of the circle?</h3>

The standard form of the equation of a circle is
x² + y² = r²

The center is represented by the horizontal (h) and vertical (k) translations. Hence,

( x - h )² + ( y - k )² = r²

Given the data in the question;

Circle center :(-3, 4)

  • h = -3
  • k = 4
  • Radius r = 7 units
  • Equation of circle = ?

Plug the given values into the equation above.

( x - h )² + ( y - k )² = r²

( x - (-3) )² + ( y - (4) )² = (7)²

( x + 3 )² + ( y - 4 )² = 49

Therefore, the equation of the circle with center (-3, 4) and radius 7 units is ( x + 3 )² + ( y - 4 )² = 49.

Learn more about equation of circle here: brainly.com/question/23799314

#SPJ1

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Solve the system of linear equations -3x+5=13 and x+4y=-10
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Read 2 more answers
If you help me just explain it to me
love history [14]

Answer:

C

Step-by-step explanation:

lets find median 2, 4, 4, 5, 6, 8, 9, 10, 10, 13, 17

now lets find the lower quartile median and upper quartile median

we don't include the median in the count, only use it to divide the data into the two parts,

2, 4, <u>4</u>, 5, 6, 8, 9, 10, 10, 13, 17

so lower quartile median is 4,

2, 4, <u>4</u>, 5, 6, 8, 9, 10, <u>10</u>, 13, 17

while upper quartile median is 10

the box represents the range between the upper quartile median and lower quartile median, thus is should go from 4 to 10 with the middle line, representing the median at 8,

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6 0
3 years ago
Hello I don’t understand question 9 a and b. Please show working out.<br> Thanks
brilliants [131]
A) I would make the positive integer x and then form an equation.

x + 30 = x^2 - 12
x + 42 = x^2
0 = x^2 - x - 42 this can be factorised
(x - 7) ( x + 6) Therefore x = 7 or x = -6

Since the question asks for a positive integer the answer is 7.

B) two positive numbers x and y.

X - y = 3
x^2 + y^2 = 117

Use these simultaneous equations to figure out each number.

Rearrange the first equation

x = y + 3

Then substitute it into the second equation.

(y+3)^2 + y^2 = 117
y^2 + 6y + 9 + y^2 = 117
2y^2 + 6y - 108 = 0
then factorise this.
(2y - 12) (y + 9)

This means that y = 6 or y = -9 but it’s 6 because that’s the only positive number.

Use y to find x

x = y + 3
x = 6 + 3
x = 9

So the answers are x = 9 and y = 6.
3 0
3 years ago
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