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Sever21 [200]
3 years ago
6

Find the image of (8,0) after a rotation of 90° about the origin.

Mathematics
1 answer:
Alinara [238K]3 years ago
8 0

Answer:

(0,8)

Step-by-step explanation:

this is my guess because 90° would move it from axis to axis, switching the x & y numbers. i could be wrong though & my appologies if i am incorrect

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Can someone help. I’m having trouble with the equation part
mote1985 [20]

Answer:

(x+3) x+7 is the answer for the first question if it's the same way my school does it. Whatever you put in parentheses is the opposite of what you think. + is going to the left. - is going to the right but those only apply when in parentheses.

7 0
3 years ago
one morning the temperature is -28 in Anchorage, Alaska, and 65 in Miami, Florida. How many degrees warmer was it in Miami than
polet [3.4K]

since the first number is negative and the 2nd is positive just add the two together

-28 + 65 = 93 degree warmer in Miami

8 0
3 years ago
4(x-1)-3(x-2)=-8<br> How do you solve this?
aleksandrvk [35]

Answer:

-10

Step-by-step explanation:

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3 years ago
Read 2 more answers
Of a group of randomly selected adults, 360 identified themselves as manual laborers, 280 identified themselves as non-manual wa
Wittaler [7]

Answer:

We are 95% confident that the percent of executives who prefer trucks is between 19.43% and 33.06%

Step-by-step explanation:

We are given that in a group of randomly selected adults, 160 identified themselves as executives.

n = 160

Also we are given that 42 of executives preferred trucks.

So the proportion of executives who prefer trucks is given by

p = 42/160

p = 0.2625

We are asked to find the 95% confidence interval for the percent of executives who prefer trucks.

We can use normal distribution for this problem if the following conditions are satisfied.

n×p ≥ 10

160×0.2625 ≥ 10

42 ≥ 10 (satisfied)

n×(1 - p) ≥ 10

160×(1 - 0.2625) ≥ 10

118 ≥ 10 (satisfied)

The required confidence interval is given by

$ p \pm z\times \sqrt{\frac{p(1-p)}{n} } $

Where p is the proportion of executives who prefer trucks, n is the number of executives and z is the z-score corresponding to the confidence level of 95%.

Form the z-table, the z-score corresponding to the confidence level of 95% is 1.96

$ p \pm z\times \sqrt{\frac{p(1-p)}{n} } $

$ 0.2625 \pm 1.96\times \sqrt{\frac{0.2625(1-0.2625)}{160} } $

$ 0.2625 \pm 1.96\times 0.03478 $

$ 0.2625 \pm 0.06816 $

0.2625 - 0.06816, \: 0.2625 + 0.06816

(0.1943, \: 0.3306)

(19.43\%, \: 33.06\%)

Therefore, we are 95% confident that the percent of executives who prefer trucks is between 19.43% and 33.06%

5 0
3 years ago
Josephine has nine chemistry books, three history books, and eight statistics books. She wants to choose one book of each type t
ikadub [295]

Answer:

20

Step-by-step explanation: add them all together

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3 years ago
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