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kow [346]
2 years ago
5

A drawing of the Eiffel Tower in Paris used the scale of 2 cm = 5 m. If the height of the tower in the drawing measures 120.4 cm

, what is the actual height of the Eiffel Tower?
Answer Choices
48.16 meters
310 meters
301 meters
602 meters
Mathematics
2 answers:
Rudik [331]2 years ago
8 0

Answer:301m

Step-by-step explanation:120.4/2=60.2 60.2*5=301

Delicious77 [7]2 years ago
3 0
301 meters

Since 2cm=5m you would have to divide 120.4 by 2 to get 60.2 and times it by 5 to get 301
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murzikaleks [220]
2x+12=33
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6 0
3 years ago
U(8, 9) and V(2, 5) are the endpoints of a line segment. What is the midpoint M of that line segment?
Pavel [41]

Answer:

The midpoint M is (5,7)

Step-by-step explanation:

m = ( \frac{x1 + x2}{2} , \frac{y1  + y2}{2} )

U(8,9)

V(2,5)

m = [(8+2)/2 , (9+5)/2]

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(Correct me if i am wrong)

5 0
3 years ago
Help please! Ty! Ratios
Kamila [148]

Answer:

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Step-by-step explanation:

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8 0
3 years ago
2. To which set or sets does the number -14
zhuklara [117]
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3 0
3 years ago
4. A triangle with base (2x+2) and height (x-2) is cut out of a rectangular sheet of paper that is (3x+4) by (2x+3) what is the
juin [17]
So what we do is
area that remains=total area-triangle area that was cut out


we need to find 2 things
total area
triangle area

total area=rectange=base times height
area=(3x+4) times (2x+3)
FOIL or distribute
6x^2+8x+9x+12=6x^2+17x+12

triangle area=1/2 times base times height
triangle area=1/2 times (2x+2) times (x-2)=
(x+2) times (x-2)=x^2+2x-2x-4=x^2-4


so
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triangle area=x^2-4

subtract
area that remains=total area-triangle area that was cut out
area that remains=6x^2+17x+12-(x^2-4)=
6x^2+17x+12-x^2+4=
6x^2-x^2+17x+12+4=
5x^2+17x+16


area that remains is 5x^2+17x+16

5 0
3 years ago
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