Answer:
I can only do 1 but I hope it helps.
Use the property of distribution:
a(b+c) = ab + ac
4(4a+5) = 4(4a) + 4(5)
4(4a+5) = 16a + 20
Hope that helps :)
Answer:
The length of the interval during which no messages arrive is 90 seconds long.
Step-by-step explanation:
Let <em>X</em> = number of messages arriving on a computer server in an hour.
The mean rate of the arrival of messages is, <em>λ</em> = 11/ hour.
The random variable <em>X</em> follows a Poisson distribution with parameter <em>λ</em> = 11.
The probability mass function of <em>X</em> is:

It is provided that in <em>t</em> hours the probability of receiving 0 messages is,
P (X = 0) = 0.76
Compute the value of <em>t</em> as follows:

Thus, the length of the interval during which no messages arrive is 90 seconds long.
Answer:
30/ 15 = 2, 2 * 12 = 24 Answer: 24 flags
Step-by-step explanation:
I split it up into 1/4’s. Hope you get at good score.
Step-by-step explanation:
1. 1/-[infinity] = 0
2. 0 - [infinity] = -∞
3. 0[infinity] = 0
4. [infinity][infinity] = IND
5. 0−[infinity] = -∞
6. [infinity]−[infinity] = ∞
7. [infinity]−e = ∞
8. 1[infinity] = ∞
9. π−[infinity] = -∞
10. π[infinity] = ∞
11. 1 −[infinity] = -∞
12. [infinity]1 = ∞
13. [infinity]−[infinity] = ∞
14. 0/[infinity] = IND
15. [infinity]0 = 0
16. 00 = 0
17. 10 = 10
18. 1 - [infinity] = -∞
19. [infinity]/0 = DNE
20. inf - inf = ∞