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Evgesh-ka [11]
2 years ago
12

The coordinates of A and B are (3k, 8) and (k, -3) respectively. Given that the gradient of the line segment AB is 3, find the v

alue of k.​
Mathematics
1 answer:
Vladimir [108]2 years ago
5 0

Step-by-step explanation:

gradient = slope or several other words.

it describes how strongly a line (or tangent to a bent curve) is going up or down or ... if it is changing at all.

it is represented by the ratio

(y coordinate change / x coordinate change)

when going from one point on the line to another.

in our case, when going from A to B we have

x changes by -2k (from 3k to k).

y changes by -11 (from 8 to -3).

so, the gradient or slope is

-11/-2k = 3

11/2k = 3

11 = 3×2k = 6k

k = 11/6

A = (33/6, 8) = (11/2, 8)

B = (11/6, -3)

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Answer:

<em>A. (1,4), (-5, 2), (7, 1), (-8, 2)</em>

Step-by-step explanation:

<u>Definition of a Function</u>

A function is a relation between an input and an output set of values with the condition that every element in the input set relates only to one element in the output set.

From the four options presented in the question, we must select the only one that doesn't repeat the value for x and has a different value of y.

For example, the set

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Answer:

\theta = 30^\circ, 330^\circ

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Step-by-step explanation:

Given [Missing from the question]

Equation:

cos\theta = \frac{\sqrt 3}{2}

Interval:

0 \le \theta \le 360

0 \le \theta \le 2\pi

Required

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The given expression:

cos\theta = \frac{\sqrt 3}{2}

... shows that the value of \theta is positive

The cosine of an angle has positive values in the first and the fourth quadrants.

So, we have:

cos\theta = \frac{\sqrt 3}{2}

Take arccos of both sides

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