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3 years ago

17. Only tenth-, eleventh-, and twelfth-grade students

Mathematics

1 answer:

Tom [10]3 years ago

4 0

Answer: Eleventh Grade

Step-by-step

The ratio of tenth graders to the school's total population is 86:255 = 33.7%.

The ratio of eleventh graders to the school's total population is 18:51 = 35.3%.

Since the probability of a student being in either tenth, eleventh, or twelfth grade = 1 = 100% (that is, certainty), then the probability of a randomly drawn student being in twelfth grade is (100-33.7-35.3)% = 31.0%.

When randomly choosing one student from the whole school, it is most likely (35.3%) that the student is in the eleventh grade.

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3 years ago

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Find the value of x so that the line passing through the points will have the given slope: (x,6) and (10,-3) with a slope of -3/

Lana71 [14]

$(x,6) \\
x_1=x \\
y_1=6 \\ \\
(10,-3) \\
x_2=10 \\ y_2=-3 \\ \\
\hbox{the slope: } m=\frac{y_2-y_1}{x_2-x_1}=\frac{-3-6}{10-x}=\frac{-9}{10-x} \\ \\
m=-\frac{3}{2} \\
\Downarrow \\
-\frac{3}{2}=\frac{-9}{10-x} \\
-\frac{3}{2}(10-x)=-9 \\
10-x=-9 \times (-\frac{2}{3}) \\
10-x=3 \times 2 \\
10-x=6 \\
-x=6-10 \\
-x=-4 \\
\boxed{x=4}$

6 0

3 years ago

The rectangle below has an area of 1 8 x 3 18x 3 square meters and a length of 2 x 2 2x 2 meters.

motikmotik

Answer:

$\text{The width of rectangle}=9x\text{ meters}$

Step-by-step explanation:

We have been given that the rectangle has an area of $18x^3$ square meters and a length of $2x^{2}$ . We are asked to find the width of rectangle.

Since we know that area of a rectangle is width times length of the rectangle, so we can find width of our given rectangle by dividing given area by length of rectangle.

$\text{Area of rectangle}=\text{Width of rectangle *Length of the rectangle}$

$\frac{\text{Area of rectangle}}{\text{Length of rectangle}}=\frac{\text{Width of rectangle *Length of the rectangle}}{\text{Legth of rectangle}}$

$\text{The width of rectangle}=\frac{\text{Area of rectangle}}{\text{Length of rectangle}}$

Upon substituting our given values in above formula we will get,

$\text{The width of rectangle}=\frac{18x^3\text{ meter}^2}{2x^2\text{ meters}}$

$\text{The width of rectangle}=\frac{9x^3\text{ meters}}{x^2}$

Using exponent rule for quotient $\frac{a^m}{a^n}=a^{m-n}$ we will get,

$\text{The width of rectangle}=9x^{3-2}\text{ meters}$

$\text{The width of rectangle}=9x^{1}\text{ meters}=9x\text{ meters}$

Therefore, width of our given rectangle will be 9x meters.

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2 years ago

6th grade math I reallyyyyy neeedd helpp

UNO [17]

Hello!

Question 6:
To find the area of the pennant, we need to multiply the length by the width.
12 x 18 = area
12 x 18 = 216
The answer is 216 square inches.

Question 7:
The perimeter of the square is 24cm and the area is 36 square cm.
The perimeter of the rectangle is 30cm and the area is 50 square cm.
They have different perimeters and different areas.

I hope this helps you! Have a great day!
-Mal

4 0

2 years ago

A boat leaves a.M. Marina at 7 AM traveling at 3.4 knots bearing is N38°E the boat docks on an island at 2pm how far north of th

Jlenok [28]

Answer:

The distance between the docks & island is 44.07 km.

Step-by-step explanation:

Speed of the boat S = 3.4 knot = 6.3 $\frac{km}{hr}$

Time taken by bot to reach the island = 7 hr

We know that the distance is given by

Distance = Speed × Time

Put all the values in above equation we get

D = 6.3 × 7

D = 44.07 km

Therefore the distance between the docks & island is 44.07 km.

6 0

2 years ago