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Korolek [52]
2 years ago
7

When Tomas simplified the expression -2.6 + (-5.4), he got 2.8. what mistake did Tomas likely make?

Mathematics
1 answer:
vladimir2022 [97]2 years ago
5 0

Tomas used incorrectly the rule of signs, the expression should be simplified as follows:

-2.6 + (-5.4)

-2.6 -5.4 = 8

<h3></h3><h3>What mistake did Tomas likely make?</h3>

Here Tomas wants to perform an addition between two numbers:

-2.6 + (-5.4)

And the outcome that Tomas gets is:

-2.6 + (-5.4) = 2.8

Here his mistake seems to bee that he thought the second number was a positive number, and he solved the operation:

-2.6 + 5.4

So, he used wrong the rule of signs.

Remember that the rule of signs says that:

(-)*(+) = (+)*(-) = (-)

Using that, we can rewrite the original expression:

-2.6 + (-5.4)

to:

-2.6 - 5.4

Solving that, we get:

-2.6 - 5.4 = -8

Which is the outcome that Tomas would have gotten if he had used correctly the rule of signs.

If you want to learn more about the rule of signs:

brainly.com/question/13333620

#SPJ1

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there are six muffins in a package how many packages will be needed to feed 48 people if each person has two muffins
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One study reports that 34​% of newly hired MBAs are confronted with unethical business practices during their first year of empl
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Answer:

z=\frac{0.28 -0.34}{\sqrt{\frac{0.34(1-0.34)}{116}}}=-1.364  

p_v =2*P(Z  

The p value obtained was a very high value and using the significance level assumed \alpha=0.05 we have p_v>\alpha so we can conclude that we have enough evidence to FAIl to reject the null hypothesis, and we can said that at 5% of significance the proportion of graduates from the previous year claim to have encountered unethical business practices in the workplace is not significant different from 0.34.  

Step-by-step explanation:

1) Data given and notation

n=116 represent the random sample taken

X represent the number graduates from the previous year claim to have encountered unethical business practices in the workplace

\hat p=0.28 estimated proportion of graduates from the previous year claim to have encountered unethical business practices in the workplace

p_o=0.34 is the value that we want to test

\alpha=0.05 represent the significance level

z would represent the statistic (variable of interest)

p_v represent the p value (variable of interest)  

2) Concepts and formulas to use  

We need to conduct a hypothesis in order to test the claim that the proportion is 0.34 or no.:  

Null hypothesis:p=0.34  

Alternative hypothesis:p \neq 0.34  

When we conduct a proportion test we need to use the z statistic, and the is given by:  

z=\frac{\hat p -p_o}{\sqrt{\frac{p_o (1-p_o)}{n}}} (1)  

The One-Sample Proportion Test is used to assess whether a population proportion \hat p is significantly different from a hypothesized value p_o.

3) Calculate the statistic  

Since we have all the info requires we can replace in formula (1) like this:  

z=\frac{0.28 -0.34}{\sqrt{\frac{0.34(1-0.34)}{116}}}=-1.364  

4) Statistical decision  

It's important to refresh the p value method or p value approach . "This method is about determining "likely" or "unlikely" by determining the probability assuming the null hypothesis were true of observing a more extreme test statistic in the direction of the alternative hypothesis than the one observed". Or in other words is just a method to have an statistical decision to fail to reject or reject the null hypothesis.  

The next step would be calculate the p value for this test.  

Since is a bilateral test the p value would be:  

p_v =2*P(Z  

The p value obtained was a very high value and using the significance level assumed \alpha=0.05 we have p_v>\alpha so we can conclude that we have enough evidence to FAIl to reject the null hypothesis, and we can said that at 5% of significance the proportion of graduates from the previous year claim to have encountered unethical business practices in the workplace is not significant different from 0.34.  

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