Answer:
A campaign manager would like to show the distribution of individuals...
Step-by-step explanation:
goodness of fit can be used to compare observed and expected counts. The newspaper report would be the expected. The campaign manager's distribution is the expected.
Answer:
Let C be the cost price of the article. Then:
C(1+30%)=marked price
So:
C(1+30%)=C(1.3)
=1.3C
If the article is then marked down 35%, then its’ price would be:
1.3C(1–35%)=1.3C(.65)
=0.845 or 84.5% of its’ cost
Then:
0.845–1=-0.155
or, a 15.5% loss on the item
Answer:
average atomic mass = 207.2172085 amu
Explanation:
To get the average atomic mass of an element using the abundance of its isotopes, all you have to do is multiply each isotope by its percentage of abundance and then sum up all the products.
For the question, we have:
203.97304 amu has an abundance of <span>1.390% (0.0139)
</span>205.97447 amu has an abundance of 24.11% (0.2411)
206.97590 amu has an abundance of 22.09% (0.2209)
207.97665 amu has an abundance of 52.41 % (0.5241)
The average atomic mass can be calculated as follows:
average atomic mass = 203.97304(0.0139) + 205.97447(0.2411)
+ 206.97590(0.2209) + 207.97665(0.5241)
average atomic mass = 207.2172085 amu
Hope this helps :)
Answer:
the correct answer is the third one
Step-by-step explanation:
When converting to milimeter from micrometer you will divide by 1000. i.e
