Answer: There can be 2 gold 1 silver, 2 silver one gold, 3 silver, or 3 gold.
I'm not really sure if this is correct but I hope this helps:)
Hey, there !
If you want to know it as a "improper fraction" , you can
Multiply the denominator from the front number
Whatever the denominator and front number is , you add it to the numerator
So, for this problem we first have the multiply the front number from the denominator
Like: 8 (40)
That gives us the answer of: 320
Now we have to add 320 to 21
Like: 320 + 21
That gives us the answer of:341
We keep our denominator (which is "40" )
Your improper fraction would be:
341 / 40
Good luck on your assignment and enjoy your day!
~MeIsKaitlyn:)
Answer:
7/18
Step-by-step explanation:
21 out of 54 = 21/54 = 7/18
Answer:
2 and 8, 3 and 5
Step-by-step explanation:
uh no explanation needed
The probability of winning exactly 21 times is 0.14 when the probability of winning the arcade game is 0.659.
We know that binomial probability is given by:
Probability (P) = ⁿCₓ (probability of 1st)ˣ x (1 - probability of 1st)ⁿ⁻ˣ
We are given that:
Probability of winning on an arcade game = P(A) = 0.659
So, the Probability of loosing on an arcade game will be = P'(A) = 1 - 0.659 = 0.341
Number of times the game is being played = 30
We have to find the Probability of winning exactly 21 times.
Here,
n = 30
x = 21
P(A) = 0.659
P'(A) = 0.341
Using the binomial probability formula, we get that:
Probability of winning exactly 21 times :
P(21 times) = ³⁰C₂₁ (0.659)²¹ x (0.341)⁷
P( 21 times ) = 0.14
Therefore, the probability of winning exactly 21 times is 0.14
Learn more about " Binomial Probability " here: brainly.com/question/12474772
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