What are some solution(s) to the quadratic equation 40 - x^2 = 0

Mathematics

1 answer:

Serhud [2]3 years ago

3 0

Answer:

x = ± 2 $\sqrt{10}$

Step-by-step explanation:

given

40 - x² = 0 ( add x² to both sides )

40 = x² or

x² = 40 ( take the square root of both sides )

x = ± $\sqrt{40}$ = ± $\sqrt{4(10)}$ = ± 2 $\sqrt{10}$

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olya-2409 [2.1K]

option C is the correct answer. sin β = 15 / 17

<u>Given data</u>

Right angled triangle has sides

opposite = 15

adjacent = 8

Hypotenuse = 17

sin β = opposite / hypotenuse

substituting the values gives

sin β = 15 / 17

Read more on SOH CAH TOA here: brainly.com/question/20020671

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