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Evgen [1.6K]
4 years ago
14

Please show work entirely! I'm giving 15 points :-)

Mathematics
1 answer:
natulia [17]4 years ago
8 0
V / 2 = 5.2 / 2.5
>> v = (5.2 / 2.5) x 2
>> v = 4.16
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Cheyenne needs to write a linear equation that is parallel to the x-axis. Which equation could she write?
barxatty [35]
Dog let me cut it to ya. Ain’t nobody gonna know that.
4 0
3 years ago
What is the value of the y-intercept of the graph of h(x) = 1.2(4.15)^x?
gizmo_the_mogwai [7]

9514 1404 393

Answer:

  h(0) = 1.2

Step-by-step explanation:

The y-intercept is h(0). When x=0, the exponential term evaluates to 1, so the y-intercept is the multiplier of the exponential term.

  h(0) = 1.2 . . . the y-intercept

7 0
3 years ago
Answer please will mark Brainly
elena55 [62]

Answer:

if im correct  i think the answer is b

Step-by-step explanation:


3 0
4 years ago
HELPPPP What is the volume of the square pyramid? Use Pythagorean’s Theorem to find the height of the pyramid
aalyn [17]

Answer: 4,111.7 mm³

Step-by-step explanation:

You need to use this formula to calculate the volume of the square pyramid:

V=\frac{s^2h}{3}

Where "s" is the lenght of any side of the square base and "h" is the height of the pyramid.

Find the height with the Pythagorean Theorem:

a^2=b^2+c^2

Where "a" is the hypotenuse and "b" and "c" are the legs of the right triangle. Let be "c" the height of the pyramid.

You can identify in the figure that:

a=26mm\\\\b=\frac{23mm}{2}=11.5mm\\\\c=h

Then, you can find the height:

(26mm)^2=(11.5mm)^2+h^2\\\\h=\sqrt{(26mm)^2-(11.5mm)^2}\\\\h=23.318mm

Then, knowing that:

s=23mm\\h=23.318mm

You can calculate the volume:

 V=\frac{(23mm)^2(23.318mm)}{3}=4,111.7mm^3

3 0
3 years ago
Assume that the weight loss for the first month of a diet program varies between 6 pounds and 14 pounds, and is spread evenly ov
Llana [10]

Hello!

For this uniform distribution, the shape of the density function is a line. We can begin by identifying key elements of the distribution:

Range: 6 to 14 pounds

Formula of density function:

y = 1/Range

1 - (14 - 6) = 1/8 = 0.125

f(x) = 0.125

1)

P(x = 7)

A uniform distribution is a continuous distribution, so the probability of x being an EXACT value is approximately 0.

<u>This is the same as if we took the following integral. (Finding the area under a curve with the same start and end point)</u>
\int\limits^a_a {f(x)} \, dx  = 0

Therefore, P(x = 7) = 0.

2)
We can think of this as finding the area of a rectangle.

The width would be the difference between 8.25 pounds and 12 pounds:
W = 12 - 8.25 = 3.75

The height would be the function (y = .125), or:
h = .125

Using the equation for the area of a rectangle: (A = h * w)

A = 3.75 * .125 = 0.469

Thus, P(8.25 < x < 12) = 0.469

3)
To find the probability GREATER than 10.50 pounds, we can subtract this value from the max value for the width:
W = 14 - 10.50 = 3.50

The height is the same as above:
h = .125

Solve for the area:
A = 3.50 * .125 = 0.4375

P(x > 10.5) = 0.4375

5 0
2 years ago
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