hope this answer helps you dear...take care!
P: quadrilaterals . I hope that helps
It probably gos like this here's my answer for number 1 6/8 and 9/12. for number 3, 10/12 and 15/18.
Answer:
First, we need to set up a (y−k)^2=4p(x−h). After plugging in all of your values, you would get (x-5)^2=-4(y-1). Now, we need to solve in terms of y by dividing each side by the factors that don't contain the variable
Step-by-step explanation:
(5*3)(2*3)=(15)(6)=90
7*3=21
21*3=63
