<h3><u>S</u><u> </u><u>O</u><u> </u><u>L</u><u> </u><u>U</u><u> </u><u>T</u><u> </u><u>I</u><u> </u><u>O</u><u> </u><u>N</u><u> </u><u>:</u></h3>
According to the question,
- Diameter of circle = 16 in
We are asked to calculate it’s circumference in terms of π.
★ Circumference of circle = 2πr
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Let us first calculate the radius of the circle.
→ Diameter = 2 × Radius
→ 16 in = 2r
→ r = 16 in ÷ 2
→ r = 8 in
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Substituting values in the formula of circumference,
→ C = 2πr
→ C = (2 × π × 8) in
→ C = 16π in
<u>Therefore</u><u>,</u><u> </u><u>1</u><u>6</u><u>π</u><u> </u><u>inches</u><u> </u><u>is</u><u> </u><u>the</u><u> </u><u>required</u><u> </u><u>answer</u><u>.</u>
Answer:
f[g(1)] = 3
General Formulas and Concepts:
<u>Pre-Algebra</u>
Order of Operations: BPEMDAS
- Brackets
- Parenthesis
- Exponents
- Multiplication
- Division
- Addition
- Subtraction
<u>Algebra I</u>
Step-by-step explanation:
<u>Step 1: Define</u>
f(x) = 2x + 1
g(x) = 3x - 2
<u>Step 2: Find g(1)</u>
- Substitute in <em>x</em>: g(1) = 3(1) - 2
- Multiply: g(1) = 3 - 2
- Subtract: g(1) = 1
<u>Step 3: Find f[g(1)]</u>
- Substitute in g(1): f[g(1)] = 2(1) + 1
- Multiply: f[g(1)] = 2 + 1
- Add: f[g(1)] = 3
Step-by-step explanation:
7/8 - 1/4 = 5/8
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