Question

Solve y = ax² + c for x.

Answer 1

In the quadratic equation y = a$x^{2}$ + c ,the value of x = ± $\sqrt \frac{y-c}{a}$

A quadratic equation is any equation containing one term wherein the unknown is squared and no term wherein it's far raised to a higher power.

A quadratic equation is an algebraic equation of the second degree in x. The quadratic equation in its standard form is ax2 + bx + c = 0, in which a and b are the coefficients, x is the variable, and c is the constant term.

To find the value of x

Assuming $a\neq o$

First, subtract c from both the sides to get:

$y-c=ax^{2}$

then, divide both sides by $a$ and transpose to get:

$x^{2} =\frac{y-c}{a}$

So, $x$ must be a square root of $\frac{y-c}{a}$  and we can deduce:

$x=$ ± $\sqrt \frac{y-c}{a}$

Learn more about quadratic equations here brainly.com/question/1214333

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