<span>Express each ratio in simplest form 18:30
</span>
![\frac{18}{30} = \frac{3}{5}](https://tex.z-dn.net/?f=%20%5Cfrac%7B18%7D%7B30%7D%20%3D%20%20%5Cfrac%7B3%7D%7B5%7D%20)
<span>
</span>
.4335
Explanation- 12 divided by $3.46 and then divide the number you get from that by 8.
Answer:
The experimental probability is 4/25
Step-by-step explanation:
Here, we want to get an experimental probability
To get this, we will need to divide the number of new customers by the total number of calls made
Mathematically, we have this as 28/175
= 4/25
Answer:
1 and 5
Step-by-step explanation:
So basically corresponding angles are the angles which lie on the same line of the transversal
And also one of them will be an interior angle and the other a exterior angle
Answer:
(a)
(b) ![450\text{ feet and }900\text{ feet}](https://tex.z-dn.net/?f=450%5Ctext%7B%20feet%20and%20%7D900%5Ctext%7B%20feet%7D)
Step-by-step explanation:
GIVEN: Suppose that the owner of a farm has
of fencing available, and they would like to enclose a rectangular portion of the land to allow animals to graze along side a straight portion of a river. The animals don't like the river water, so fencing is not necessary along the river.
TO FIND: What is the largest area that they can enclose using the fencing? What are the necessary dimensions of fencing in order to achieve that area?
SOLUTION:
Let the length and width of area enclosed be ![a\text{ and }b](https://tex.z-dn.net/?f=a%5Ctext%7B%20and%20%7Db)
as one side of area does not require fencing, total perimeter of rectangular portion.
![2a+b=1800](https://tex.z-dn.net/?f=2a%2Bb%3D1800)
![b=1800-2a](https://tex.z-dn.net/?f=b%3D1800-2a)
Area of rectangular portion ![=\text{length}\times\text{width}](https://tex.z-dn.net/?f=%3D%5Ctext%7Blength%7D%5Ctimes%5Ctext%7Bwidth%7D)
![=ab](https://tex.z-dn.net/?f=%3Dab)
putting value of
in equation
![area=a(1800-2a)](https://tex.z-dn.net/?f=area%3Da%281800-2a%29)
![area=1800a-2a^2](https://tex.z-dn.net/?f=area%3D1800a-2a%5E2)
to maximize area ![\frac{d(area)}{da}=0](https://tex.z-dn.net/?f=%5Cfrac%7Bd%28area%29%7D%7Bda%7D%3D0)
![1800-4a=0](https://tex.z-dn.net/?f=1800-4a%3D0)
![a=450\text{ feet}](https://tex.z-dn.net/?f=a%3D450%5Ctext%7B%20feet%7D)
now,
![b=1800-2a](https://tex.z-dn.net/?f=b%3D1800-2a)
![b=900\text{ feet}](https://tex.z-dn.net/?f=b%3D900%5Ctext%7B%20feet%7D)
area of rectangular portion ![=450\times900=405000\text{ feet}^2](https://tex.z-dn.net/?f=%3D450%5Ctimes900%3D405000%5Ctext%7B%20feet%7D%5E2)
Hence largest area of enclosure is
and length and width are ![450\text{ feet and }900\text{ feet}](https://tex.z-dn.net/?f=450%5Ctext%7B%20feet%20and%20%7D900%5Ctext%7B%20feet%7D)