The complete question in the attached figure
we have that
tan a=7/24 a----> III quadrant
cos b=-12/13 b----> II quadrant
sin (a+b)=?
we know that
sin(a + b) = sin(a)cos(b) + cos(a)sin(b<span>)
</span>
step 1
find sin b
sin²b+cos²b=1------> sin²b=1-cos²b----> 1-(144/169)---> 25/169
sin b=5/13------> is positive because b belong to the II quadrant
step 2
Find sin a and cos a
tan a=7/24
tan a=sin a /cos a-------> sin a=tan a*cos a-----> sin a=(7/24)*cos a
sin a=(7/24)*cos a------> sin²a=(49/576)*cos²a-----> equation 1
sin²a=1-cos²a------> equation 2
equals 1 and 2
(49/576)*cos²a=1-cos²a---> cos²a*[1+(49/576)]=1----> cos²a*[625/576]=1
cos²a=576/625------> cos a=-24/25----> is negative because a belong to III quadrant
cos a=-24/25
sin²a=1-cos²a-----> 1-(576/625)----> sin²a=49/625
sin a=-7/25-----> is negative because a belong to III quadrant
step 3
find sin (a+b)
sin(a + b) = sin(a)cos(b) + cos(a)sin(b)
sin a=-7/25
cos a=-24/25
sin b=5/13
cos b=-12/13
so
sin (a+b)=[-7/25]*[-12/13]+[-24/25]*[5/13]----> [84/325]+[-120/325]
sin (a+b)=-36/325
the answer issin (a+b)=-36/325
Answer:
a). Nadia made a total of $825 last week in commission sales
b). The total amount Nadia in commission in 2011=$42,900
Step-by-step explanation:
Step 1
Express the amount in commission she earns from her sales as follows;
C=S×r
where;
C=commission earned
S=total value of stock sales
r=commission rate
In our case;
C=unknown
S=$7,500
r=11%=11/100=0.11
replacing;
C=11% of 7,500
C=(11/100)×7,500
C=0.11×7,500=825
Nadia made a total of $825 last week in commission sales
b). To express the total amount she made in 2011, we derive the formula below;
Total amount (2011)=Average weekly commission×number of weeks in 2011
where;
Average weekly commission=$825
number of weeks in 2011=52
replacing;
Total amount (2011)=(825×52)=42,900
The total amount Nadia in commission in 2011=$42,900
Normally when dealing with coins the probability of getting heads or tails is 0.5 each. However in this case since its an unfair coin, the probability of getting heads is 0.2.
H - head
T - tails
R - red marble
pr (H) = 0.2
urn
6 red and 4 blue
pr (T) = 0.8
urn
3 red and 5 blue
when heads is obtained
red - 6/10 -0.6
blue - 4/10 - 0.4
therefore when multiplying with 0.2 probability of getting heads
pr (R ∩ H) red - 0.6*0.2 = 0.12
when tails is obtained
red - 3/8 - 0.375
blue - 5/8 - 0.625
when multiplying with 0.8 probability of getting tails
pr (R ∩ T) red - 0.375 * 0.8 = 0.3
using bayes rule the answer can be found out,
the following equation is used;
pr (H | R) = pr (R ∩ H) / {pr (R ∩ H) + pr (R ∩ T)}
= 0.12 / (0.12 + 0.3)
= 0.12 / 0.42
= 0.286
the final answer is 0.286
Answer:
answer is the 2nd one
Step-by-step explanation:
y = 1/3(3) - 1 = 1 - 1 = 0 (3,0)
y = 1/3(0) - 1 = 0 - 1 = -1 (0, -1)
y= 1/3(6) - 1 = 2 - 1 = 1 (6, 1)
Answer: Abraham could run 8 miles each day for 3 days and get 24. He could run 6 miles each day for 4 days and get 24.
Abraham can run 10 miles each day for 3 days and get 30 or he could run 7.5 miles a day for 4 days and get 30.
Not sure if this is the answer it wants or not