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nadya68 [22]
3 years ago
15

A (n) ?graph consists of distinct, isolated points

Mathematics
1 answer:
Alex_Xolod [135]3 years ago
5 0

The answer is discrete graph

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For the given table of values for a polynomial function, where must the zeros of the function lie?
Jet001 [13]

Answer:

A. Between 3.0 and 3.5 and between 4.0 and 4.5

Step-by-step explanation:

The zeroes of a function occur whenever a value of x returns zero. To predict where the zeroes lie, determine the interval(s) where the function crosses the x-axis. This occurs when either f(x) goes from a negative value to a positive value or vice versa.

From x=3.0 and x=3.5, the y-values go from 4.0 (positive) to -0.2 (negative), respectively. Therefore, there must be a zero in this interval.

From x=4.0 and x=4.5, the y-values go from -0.8 (negative) to 0.1 (positive), respectively. Therefore, there must also be a zero in this interval.

Thus, the zeros of this function occur between 3.0 and 3.5 and between 4.0 and 4.5, leading to answer choice A.

7 0
3 years ago
What is the prime factorization of 35? 1 • 35 12 • 5 • 7 1 • 5 • 7 5 • 7
Nonamiya [84]

Answer:

  5·7

Step-by-step explanation:

From your knowledge of multiplication tables, you know that ...

  5×7 = 35

Both 5 and 7 are prime numbers, so that is the prime factorization.

4 0
3 years ago
Prove ABE congruent ACD​
solmaris [256]
IS aB || ac I THINK
3 0
3 years ago
PLEASE HELP ME QUICKKKKK
icang [17]
(3)

It says the rocket was in the air for approximately 6 seconds before hitting the ground.

But the graph proves it untrue because after 6 seconds it is still in the air, rather than on the ground like (3) suggests.
8 0
2 years ago
Write an equation for the perpendicular bisector of the line segment joining the two points.
Leona [35]
Points (1, 7)  and  (-3, 2)

Slope for a line between (x₁, y₁) and (x₂, y₂) , m = (y₂ -y₁) / (x₂- x₁)

The slope for the line joining the two points =  (2 - 7) / (-3 - 1) = -5/-4

Slope = 5/4

Hence the perpendicular bisector would have a slope of -1/(5/4) = -4/5

By condition of perpendicularity

For points (1, 7)  and  (-3, 2),

Formula for midpoints for (x₁, y₁) and (x₂, y₂) is ((x₁ +x₂)/2 , (y₁+ y₂)/2)

Midpoint for (1, 7)  and  (-3, 2) = ((1+ -3)/2 , (7+2)/2) = (-2/2, 9/2)

= (-1, 9/2)

Since the slope of perpendicular bisector is -4/5 and passes through the midpoint (-1, 9/2)

Equation  y - y₁ = m (x - x₁)

                y - 9/2 = (-4/5) (x - -1)
           
                y - 9/2 = (-4/5)(x + 1)

               5(y - 9/2) = -4(x + 1)

               5y - 45/2 = -4x - 4

                 5y =  -4x - 4 + 45/2
           
                5y + 4x = 45/2 - 4

                  5y + 4x = 22  1/2  - 4 =  18 1/2

                  5y + 4x =  37/2

                  10y + 8x = 37

The equation of the line to perpendicular bisector is 10y + 8x = 37
7 0
3 years ago
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