Given that 3x^2-3x+2 find each of the following. a) g(0) b) g() c) g() d) g(x) e) g(1t)
1 answer:
The resulting values and function are 2, 8, 20, 3x^2+3x + 2 and 3t^2-9t+8
<h3>Functions and values</h3>Given the following equation expressed as;
f(x) = 3x^2-3x+2
We are to find the following function;
a) g(0) = 3(0)^2-3(0) + 2
g(0) = 2
b) g(-1) = 3(-1)^2-3(-1) + 2
g(-1) = 3+3+2
g(-1) = 8
c) g(3)= 3(3)^2-3(3) + 2
g(3) = 27-9+2
g(3) = 20
d) g(-x) = 3(-x)^2-3(-x) +2
g(-x) = 3x^2+3x + 2
e) g(1-t) = 3(1-t)^2-3(1-t) + 2
g(1-t) = 3(1-2t+t^2)-3t+3 + 2
g(1-t) = 3-6t+3t^2-3t+5
g(1-t) = 3t^2-9t+8
Hence the resulting values and function are 2, 8, 20, 3x^2+3x + 2 and 3t^2-9t+8
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Answer:
40 feet
Step-by-step explanation:
Given : The deck is at a height of 520 ft. She sees her friend on the ground below at an angle of depression of 85.6 degrees.
To Find : What is the distance between the two? Round your answer to the nearest tenth of a foot.
Solution :
Refer the attached figure
Height of deck =AB =520 ft.
Angle of depression ∠C = 85.6°
We are supposed to find length of BC i.e. distance between two.
We will use trigonometric ratios :
Thus the distance between two is 40 feet
