Question

Given that ​3x^2-3x+2 find each of the following. ​a) ​g(0) ​b) ​g(​) ​c) ​g(​) ​d) ​g(​x) ​e) ​g(1​t)

Answer 1

The resulting values and function are 2, 8, 20, 3x^2+3x + 2 and 3t^2-9t+8

Functions and values

Given the following equation expressed as;

f(x) = 3x^2-3x+2

We are to find the following function;

a) g(0) = 3(0)^2-3(0) + 2

g(0) = 2

b) g(-1) = 3(-1)^2-3(-1) + 2

g(-1) = 3+3+2
g(-1) = 8

c) g(3)= 3(3)^2-3(3) + 2

g(3) = 27-9+2
g(3) = 20

d) g(-x) = 3(-x)^2-3(-x) +2

g(-x) = 3x^2+3x + 2

e) g(1-t) = 3(1-t)^2-3(1-t) + 2

g(1-t) = 3(1-2t+t^2)-3t+3 + 2

g(1-t) = 3-6t+3t^2-3t+5

g(1-t) = 3t^2-9t+8

Hence the resulting values and function are 2, 8, 20, 3x^2+3x + 2 and 3t^2-9t+8

Learn more on functions and values here; brainly.com/question/6561461

#SPJ1