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MrMuchimi
3 years ago
13

In a mixture of​ concrete, there are fourfour lb of cement mix for each pound of gravel. If the mixture contains a total of 2952

95 lb of these two​ ingredients, how many pounds of gravel are​ there?
Mathematics
1 answer:
Anton [14]3 years ago
3 0

Answer: there are 59059 lbs of gravel.

Step-by-step explanation:

In a mixture of​ concrete, there are four lbs of cement mix for each pound of gravel. This means that eight lbs of cement would be mixed for 2 pounds of gravel and 12 lbs of cement would be mixed for 3 pounds of gravel and 12. Therefore, the constant ratio of cement to gravel is 4:1

The total ratio is 4 + 1 = 5

If the mixture contains a total of 295295 lb of these two​ ingredients, then the number of pounds of gravel that are​ there is

1/5 × 295295 = 59059 lbs

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A number was subtracted from 15. After which, that result was multiplied by 5. This result was then divided by 5 for a result of
likoan [24]

Answer:

14

Step-by-step explanation:

15-14 = 1

1*5=5

5/1=1

6 0
3 years ago
Which of the following represents the ratio of the hypotenuse to the given side?
mixas84 [53]

Answer:c

Step-by-step explanation:

hyp=6\sqrt{2}

adj=6

hyp:adj=6\sqrt{2}  :2

hyp:adj=\frac{6\sqrt{2} }{6} \\

=\frac{\sqrt{2} }{1} \\hyp:adj=\sqrt{2} :1

3 0
3 years ago
What is the product of the binomals below (2x+3) (3x+3)
Korvikt [17]

Answer:

3*(2x+3)*(x+1)

Step-by-step explanation:

pull like terms from the problem to re-arrange it into a product

\left(2x+3\right)\left(3x+3\right)\\3x + 3  =   3 \cdot (x + 1)\\3 \cdot (2x + 3) \cdot (x + 1)\\

5 0
2 years ago
A manufacturing company produces 3 different products A, B, and C. Three types of components, i.e., X, Y, and Z, are used in the
Murljashka [212]

Answer:

Step-by-step explanation:

Using the Excel Formula:

Decision    Variable        Constraint              Constraint

A                     65                          65                         100

B                     80                          80                         80

C                     90                         90                          90

                      14100                    300                        300

= (150 *B3)+(80*B4) +(65*B5)-(100-B3+80-B4+90-B5)*90

Now, we have:

Suppose A, B, C represent the number of units for production A, B, C which is being manufactured

                             A              B                  C                Unit price

Need of X          2                 1                   1                     $20

Need of Y           2                3                  2                    $30

Need of Z           2                2                  3                    $25

Price of  

manufac -      $200          $240            $220      

turing

Now,  for manufacturing one unit of A, we require 2 units of X, 2 units of Y, 2 units of Z are required.  

Thus, the cost or unit of manufacturing of A is:

$20 (2) + $30(2) + $25(2)

$(40 + 60 + 50)

= $150

Also, the market price of A = $200

So, profit = $200 - $150 = $50/ unit of A

Again;

For manufacturing one unit of B, we require 1 unit of X, 3 units of Y, and 2 units of Z are needed and they are purchased at $20, $30, and 425 each.

So, total cost of manufacturing a unit of B is:

= $20(1) + $30(3) + $25(2)

= $(20 + 90+50)

= $160

And the market price of B = $240

Thus, profit = $240- $160  

profit = $80

For manufacturing one unit of C, we have to use 1 unit of X, 2 unit of Y, 3 units of Z are required:

SO, the total cost of manufacturing a unit of C is:

= $20 (1) + $30(2) + $25(3)

= $20 + $60 + $25

= $155

This, the profit = $220 - $155 = $65

However; In manufacturing A units of product A, B unit of product B & C units of product C.

Profit  --> 50A + 80B + 65C

This should be provided there is no penalty for under supply of there is under supply penalty for A, B, C is $40

The current demand is:

100 - A

80 - B

90 - C respectively

So, the total penalty

{(100 - A) + (80 - B) +(90 - C) } + \$40

This should be subtracted from profit.

So, we have to maximize the profit  

Z = 50A + 80B + 65C = {(100 -A) + (80 - B) + (90 - C)};

Subject to constraints;

we have the total units of X purchased can only be less than or equal to 300 due to supplies capacity

Then;

2A + B +C \le 300 due to 2A, B, C units of X are used in manufacturing A, B, C units of products A, B, C respectively.

Next; demand for A, B, C will not exceed 100, 80, 90 units.

Hence;

A \le 100

B \le 80

C \le 90

 

and A, B, C \ge 0 because they are positive quantities

The objective is:

\mathbf{Z = 50A + 80B + 65 C - (100 - A + 80 - B + 90 - C) * 40}

A, B, C \to Decision Varaibles;

Constraint are:

A \le 100 \\ \\  B \le 100 \\ \\ C \le 90 \\ \\2A + B + C \le 300 \\ \\ A,B,C \ge 0

6 0
3 years ago
I have no idea how to do this, pls help. Question in the picture. Please show your work. Thanks!
geniusboy [140]

Answer:

C

Step-by-step explanation:

This is a stem and leaf plot. If you don't know what a stem and leaf plot is, try searching it before coming back and viewing the solution. I also see an "example" button. It might help to hit that too.

First, we sort the list of numbers. Here is what we get:

64, 66, 67, 68, 69, 74, 75, 76, 78, 79

Here, the stems are the tens digits and the leaves are the ones digits.

Therefore, for the stem 6, the leaves are:

4, 6, 7, 8, 9

For the stem 7, the leaves are:

4, 5, 6, 8, 9

The answer, I believe, is C

4 0
3 years ago
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