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3 years ago

Can I get help on number 7!!!!!

Mathematics

1 answer:

Ratling [72]3 years ago

3 0

Answer:

C =(43/55)R; C - R = 8t; 48 mi

Step-by-step explanation:

Let C = the distance a coyote can run in t hours.

Let R = the distance a rabbit can run in t hours.

(1) C = 43t

(2) R = 35t

A. Two equivalent expressions

(a) C/R = 43/35

C = (43/55)R

(b) C – R = 43t – 35t

C – R = 8t

B. Distance advantage of coyote

Let the difference D = C - R

D = 8t

D = 8 × 6

D = 48 mi

In 6 h, the coyote can run 48 mi further than the rabbit.

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Solve for l, 2l+8=36

inna [77]

Step-by-step explanation:

2I+8=36

2I=36-8

2I=28

I=28/2

I=14

4 0

3 years ago

LA plane is trying to travel 250 miles at a bearing of 20° E of S, however, it ends 230 miles away from the

Semmy [17]

Answer:

The wind pushed the plane $65.01$ miles in the direction of $45.56 ^{\circ}$ East of North with respect to the destination point.

Step-by-step explanation:

Let origin, O, br the starting point and point D be the destination at 250 miles at a bearing of 20° E of S, but due to wind let D' be the actual position of the plane at 230 miles away from the starting point in the direction of 35° E of South as shown in the figure.

So, we have |OD|=250 miles and |OD'|=230 miles.

Vector $\overrightarrow{DD'}$ is the displacement vector of the plane pushed by the wind.

From figure, the magnitude of the required displacement vector is

$|DD'|=\sqrt{|AB|^2+|PQ|^2}\;\cdots(i)$

and the direction is $\alpha$ east of north as shown in the figure,

$\tan \alpha=\frac{|PQ|}{|AB|}\;\cdots(ii)$

From the figure,

$|AB|=|OA-OB|$

$\Rightarrow |AB|=|OD\cos 20 ^{\circ}-OD'\cos 35 ^{\circ}|$

$\Rightarrow |AB|=|250\cos 20 ^{\circ}-230\cos 35 ^{\circ}|$

$\Rightarrow |AB|=45.52$ miles

Again, $|PQ|=|OP-OQ|$

$\Rightarrow |PQ|=|OD\sin 20 ^{\circ}-OD'\sin 35 ^{\circ}|$

$\Rightarrow |PQ|=|250\sin 20 ^{\circ}-230\sin 35 ^{\circ}|$

$\Rightarrow |PQ|=46.42$ miles

Now, from equations (i) and (ii), we have

$|DD'|=\sqrt{|45.52|^2+|46.42|^2}=65.01$ miles, and

$\tan \alpha=\frac{|46.42|}{|45.52|}$

$\alpha=\tan^{-1}\left(\frac{|46.42|}{|45.52|}\right)=45.56 ^{\circ}$

Hence, the wind pushed the plane $65.01$ miles in the direction of $45.56 ^{\circ}$ E astof North with respect to the destination point.

5 0

3 years ago

Please help me out. I need help ASAP

katrin [286]

B and D and C in that order

4 0

3 years ago

Read 2 more answers

Which statement best describes why liquid water exists on Earth?

Vikki [24]

Complete Question:

Which statement best describes why liquid water exists on earth?

A. Earth experiences comet crashes and volcanic eruptions.

B. Earth experiences a strong magnetic field and lunar tides.

C. Earth has moderate temperatures and a strong gravitational force.

D. Earth has hydrogen bonds with the sun

Correct Answer:

Earth has a moderate temperature and strong gravitational force. This is the reason for existence of liquid water on Earth.

Step-by-step explanation:

Liquid water has the chemical formula of H₂O. So it is composed of mainly hydrogen and oxygen molecules with the present of different materials present in it based on the place it is located. As the water molecules are bonded by weak van der waals bond, it can be easily broken with the boiling point of 100 °C.

Thus, the existence of liquid water is possible in moderate temperature. Also the strong gravitational force of Earth helps to keep the liquid water stable in Earth. Thus, the strong gravitational force and the moderate temperature condition of Earth is responsible for liquid water existence on Earth.

8 0

3 years ago

I need to find the distance between pairs of integers like 8 and 32; 15 and 64; and -27 and 18. How do I do this?

Alona [7]

Answer:

i believe you have to divide 8 by each number to get the distance between the pairs of integers.

Step-by-step explanation:

5 0

3 years ago