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2 years ago

A) Write each expression in expanded form. B) Then calculate the value of the

Mathematics

1 answer:

Tatiana [17]2 years ago

8 0

A) (3)² = 3 × 3 and 10(8)² = 10 × 8 × 8

B) (3)² = 9 and 10(8)² = 640

For any number x, the square of the number denoted by (x)² is equal to 2 times x multiplied by itself or x*x.

Here, we are given two expressions- (3)² and 10(8)²

we need to write both of them in expanded form and then write their values.

Expanded form of (3)² is 3 × 3

The value of the expression (3)² will be-

(3)² = 3 × 3 = 9

Similarly, expanded form of 10(8)² is 10 × 8 × 8

The value of the expression 10(8)² will be-

10(8)² = 10 × 8 × 8 = 640

Learn more about expanded form here-

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5(5t + 1) = 25t-7<br> Can someone help me with this solution??

masha68 [24]

Firstly you multiply 5 with everything in the brackets on the left side of = . and than you put t on the left side and change sign (if it was + then its going to be -) and numbers on right side and do the same with signs. then just calculate the rest

5(5t +1) = 25t - 7
25t + 5 = 25t - 7
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3 years ago

How much longer is a 12cm pencil than a 1 dm pen

Alexxx [7]

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3 years ago

The accompanying data resulted from an experiment in which weld diameter x and shear strength y (in pounds) were determined for

saul85 [17]

Answer:

y hat = 2114.20 + 18.96x

Step-by-step explanation:

Given the least square regression model equation:

y hat = -959.00 + 8.60x

weld diameter x ; shear strength y (in pounds)

1 lb = 0.4536 kg

To express shear strength y in kilogram:

y is multiplied by 0.4536

(y hat × 0.4536) = -959.00 + 8.60x

Divide both sides by 0.4536

(y hat × 0.4536) / 0.4536= (-959.00 + 8.60x) / 0.4536

y hat = 2114.1975 + 18.959435x

y hat = 2114.20 + 18.96x

7 0

3 years ago

Seven times the difference of a number and 1

weeeeeb [17]

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3 years ago

Read 2 more answers

single die is rolled twice. Find the probability of rolling an oddodd number the first time and a number greater than 33 the sec

givi [52]

Answer:

$\frac{1}{4}$

Step-by-step explanation:

A single die is rolled twice, we have to find the probability of rolling an odd number in first throw and a number greater than 3 in the second throw.

a) Rolling an Odd number in first throw

A die has total 6 possible outcomes, out of which 3 are odd numbers i.e. 1,3 and 5

So, total number of possible outcomes = 6

Total Favorable outcomes (Odd numbers) = 3

Probability is defined as the ratio of favorable outcomes to total number of outcomes. So,

The probability of rolling an odd number would be = $\frac{3}{6} = \frac{1}{2}$

b) Rolling a number greater than 3 in second throw

Here again total possible outcomes = 6

Favorable outcomes (Numbers greater than 3 are 4, 5 and 6) = 3

So,

The probability of rolling a number greater than 3 = $\frac{3}{6} = \frac{1}{2}$

These two events(rolls) are independent of each other, so the overall probability of both events occurring would be the product of individual probabilities.

So,

Probability of rolling an odd number the first time and a number greater than 3 the second time = $\frac{1}{2} \times \frac{1}{2} = \frac{1}{4}$

6 0

3 years ago