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katovenus [111]
2 years ago
14

A) Write each expression in expanded form. B) Then calculate the value of the

Mathematics
1 answer:
Tatiana [17]2 years ago
8 0

A) (3)² = 3 × 3 and 10(8)² = 10 × 8 × 8

B) (3)² = 9 and 10(8)² = 640

For any number x, the square of the number denoted by (x)² is equal to 2 times x multiplied by itself or x*x.

Here, we are given two expressions- (3)² and 10(8)²

we need to write both of them in expanded form and then write their values.

Expanded form of (3)² is 3 × 3

The value of the expression (3)² will be-

(3)² = 3 × 3 = 9

Similarly, expanded form of 10(8)² is 10 × 8 × 8

The value of the expression 10(8)² will be-

10(8)² = 10 × 8 × 8 = 640

Learn more about expanded form here-

https://brainly.in/question/19612773

#SPJ9

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1,232 divided by 8 =?<br> Show your work!
zysi [14]

Answer:

154

Step-by-step explanation:

just divide 1232 and 8

(long division)

4 0
3 years ago
Misty and Yesenia have a group of Base Ten Blocks. Misty has six more blocks than Yesenia. Yesenia's blocks represent 17. Togeth
nignag [31]

Answer:

Yesenia has qty 1 of 10s and qty 7 of 1s

Misty has qty 6 of 10s and qty 8 of 1s

<u>Step-by-step explanation:</u>

Note that there are two different types of blocks: 1s and 10s.  Let x represent the number of 10s and y represent the number of 1s.

                   <u>Value of the blocks </u>                         <u>Number of blocks</u>

Yesenia:           1x + 7y                                                   8

Misty:          <u>                                   </u>                         <u>                             </u>

Total:                8x + 5y                                                 22


Start with the number of blocks that Misty has: 22 - 8 = 14

Next, how many 1s can be added to Yesenia's to make 5? 15 - 7 = 8

How many blocks are left over from Misty's 14? 14 - 8 = 6

********************************************************************************************

Fill in the information:

                   <u>Value of the blocks </u>                         <u>Number of blocks</u>

Yesenia:           1x + 7y                                                  8

Misty:          <u>      6x + 8y                 </u>                         <u>      14                   </u>

Total:                8x + 5y                                                 22

4 0
3 years ago
Andre and Elena are each saving money Andre starts with $100 in his savings account and adds five dollars per week Elena starts
densk [106]

Answer: Andre

Step-by-step explanation: coz I juss know..

7 0
3 years ago
Read 2 more answers
3x -2=13 what is x ...........
Tom [10]
Methods:

3x-2=13

=> 
3x-2+2=13+2

=> 
3x+0=15

=> 
3x=15

=> 
\frac{3}{3}x= \frac{15}{3}

=> 
x =  \frac{5}{1} or 5

or, (do side changing)

3x-2=13

=> 3x=13+2

=> 3x=15

=> x= \frac{15}{3}

=> x= \frac{5}{1} or 5


3 0
4 years ago
Read 2 more answers
Assume that the number of messages input to a communication channel in an Exponential distribution with 7 messages arriving in a
NARA [144]

The probability that more than 3 messages will arrive during a 30-second interval is P(X=n)=\dfrac{e^{-0.3 \times 20} (0.3 \times 20)^n}{n!}.

According to the statement

we have given that the an Exponential distribution with 7 messages arriving in a 10 second period and we have to find the probability that more than 3 messages will arrive during a 30-second interval.

So, For this purpose, we know that the

The probability is the measure of the likelihood of an event to happen. It measures the certainty of the event.

And the given information is that :

3 messages will arrive during a 30-second interval.

Then

Probability = P(X=1) + P(X=2) + P(X=3).Then

The probability become according to the exponential distribution:

P(X=1)=\dfrac{e^{-0.3 \times 20} (0.3 \times 20)^1}{1!}\\P(X=2)=\dfrac{e^{-0.3 \times 20} (0.3 \times 20)^2}{2!}\\P(X=3)=\dfrac{e^{-0.3 \times 20} (0.3 \times 20)^3}{3!}\\

And then substitute the values in it then

Probability = \dfrac{e^{-0.3 \times 20} (0.3 \times 20)^1}{1!}\ +\dfrac{e^{-0.3 \times 20} (0.3 \times 20)^2}{2!}\ + \dfrac{e^{-0.3 \times 20} (0.3 \times 20)^3}{3!}\\

This is the probability.

So, The probability that more than 3 messages will arrive during a 30-second interval is P(X=n)=\dfrac{e^{-0.3 \times 20} (0.3 \times 20)^n}{n!}.

Learn more about probability here

brainly.com/question/24756209

#SPJ4

7 0
2 years ago
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