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Yakvenalex [24]
3 years ago
8

I don't know i just need help with this quiz ok

Mathematics
1 answer:
ololo11 [35]3 years ago
5 0
The answer is 73....
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Is it possible for a system of linear equations to have no solutions ?
sveta [45]
Yes it is possible,t<span>hey never intersect, so there is </span>no<span> point that lies on both lines, and </span>no solution<span> to the </span><span>system</span>
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3 years ago
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550 tickets were sold for a game for a total of $712.50. If adult tickets sold for $1.50 and children's tickets sold for $1.00,
EastWind [94]

9514 1404 393

Answer:

  • adult: 325
  • children's: 225

Step-by-step explanation:

It usually works well to let a variable represent the higher-value item in the mix. Here, we can let 'a' represent the number of adult tickets sold. Then the total revenue is ...

  1.50a +1.00(550 -a) = 712.50

  0.50a = 162.50 . . . . . . . . . . . . . subtract 550 and collect terms

  a = 325

  c = 550 -325 = 225

325 adult and 225 children's tickets were sold.

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2 years ago
I need help finding out what AC is!!
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5 0
3 years ago
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The 6 elephants at the zoo have a combined weight of 11,894 pounds. About how much does each elephant weigh?
Sidana [21]

Answer: 14,000 i think

Step-by-step explanation:

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2 years ago
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Use the Central Limit Theorem to find a mean given a probability Question A video game company sells an average of 132 games a m
aev [14]

Answer:

The number of games must a store sell in order to be eligible for a reward is 135.

Step-by-step explanation:

Let the random variable <em>X</em> represent the number of video games sold in a month by the sores.

The random variable <em>X</em> has a mean of, <em>μ</em> = 132 and a standard deviation of, <em>σ</em> = 9.

It is provided that the company is looking to reward stores that are selling in the top 7%.

That is, P (\bar X > \bar x) = 0.07.

The <em>z</em>-score related to this probability is, <em>z</em> = 1.48.

Compute the number of games must a store sell in order to be eligible for a reward as follows:

z=\frac{\bar x-\mu}{\sigma/\sqrt{n}}

\bar x=\mu+z\cdot \sigma/\sqrt{n}

   =132+1.48\times (9/\sqrt{36})\\\\=132+2.22\\\\=134.22\\\\\approx 135

Thus, the number of games must a store sell in order to be eligible for a reward is 135.

5 0
3 years ago
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