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Yakvenalex [24]
3 years ago
8

I don't know i just need help with this quiz ok

Mathematics
1 answer:
ololo11 [35]3 years ago
5 0
The answer is 73....
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An item is priced at $80. It is on sale for 20% off the regular price. What is the sale price?
Masja [62]
Regular Pirce = $80.

Discount = 20%

Discount = 20% x $80 = 0.2 x 80 = $16

Sale Price = 80 - 16 = $64

----------------------------------------------------
Answer: The Sale Price is $64.
----------------------------------------------------
4 0
3 years ago
Riley has set up a six week payment schedule to pay for his upcoming school camp. he has already put down a 15 percent deposit a
anyanavicka [17]

Answer:

$32.30 each week

Step-by-step explanation:

Deposit = 15%  = $34.20

⇒ total cost of camp = (34.20 ÷ 15) x 100 = $228

Balance left after deposit = 228 - 34.20 = $193.80

If paying the remaining balance in 6 weekly installments,

⇒ weekly payment = 193.80 ÷ 6 = $32.30

4 0
2 years ago
What are the solution(s) to the quadratic equation 50 – x2 = 0?
Paraphin [41]

Answer:

No real solution

Step-by-step explanation:

There is no perfect squares in 50

6 0
3 years ago
Read 2 more answers
The overhead reach distances of adult females are normally distributed with a mean of 195 cm and a standard deviation of 8.3 cm.
UNO [17]

Answer:

Mean : \mu = 195

\sigma = 8.3 cm

a) Find the probability that an individual distance is greater than 204.30 cm.

We are supposed to find P(Z>204.30)

x = 204.30

Formula : z=\frac{x-\mu}{\sigma}

Substitute the value sin the formula :

z=\frac{204.40-195}{8.3}

z=1.13253

P(Z>204.30)=1-P(Z<204.30)

Refer the z table

P(Z>1.13253)=1-P(Z<1.13253)

P(Z>1.13253)=1-0.8708

P(Z>1.13253)=0.1292

The probability that an individual distance is greater than 204.30 cm is 0.1292.

b) Find the probability that the mean for 20 randomly selected distances is greater than 192.80 cm

We are supposed to find P(Z>192.80)

x = 192.80

Formula : z=\frac{x-\mu}{\sigma}

Substitute the value sin the formula :

z=\frac{ 192.80-195}{8.3}

z=-0.265

P(Z>192.80)=1-P(Z<192.80)

Refer the z table

P(Z>-0.265)=1-P(Z<-0.265)

P(Z>-0.265)=1-0.3974

P(Z>-0.265)=0.6026

The probability that the mean for 20 randomly selected distances is greater than 192.80 cm is 0.6026

c)  Why can the normal distribution be used in part​ (b), even though the sample size does not exceed​ 30

The normal distribution is used because the original population has normal distribution.

3 0
3 years ago
Please help me with 20 through 22 please I really appreciate it! Thank you very much!
Ivahew [28]

Answer:

20. 2x+y

21. 4

22. x+y

Step-by-step explanation:

20. <u>9</u><u>x</u><u>+</u><u>2</u><u>y</u><u> </u>- <u>x-2</u><u>y</u><u> </u><u> </u> find your LCM

4 4

=<u>(</u><u>9</u><u>x</u><u>+</u><u>2</u><u>y</u><u>)</u><u>-</u><u>(</u><u>x-2y</u><u>)</u><u> </u> clear bracket

<u> </u><u> </u><u> </u><u> </u><u> </u><u> </u><u> </u><u> </u><u> </u><u> </u><u> </u><u> </u><u> </u><u> </u><u> </u><u> </u><u> </u><u> </u><u> </u>4

=<u>9</u><u>x</u><u>+</u><u>2</u><u>y</u><u>-</u><u>x</u><u>+</u><u>2</u><u>y</u><u> </u> collect terms

4

=<u>9</u><u>x</u><u>-</u><u>x</u><u>+</u><u>2</u><u>y</u><u>+</u><u>2</u><u>y</u>

<u> </u> 4

=<u>8</u><u>x</u><u>+</u><u>4</u><u>y</u><u> </u> factorize

<u> </u><u> </u><u> </u><u> </u><u> </u><u> </u><u> </u><u> </u><u> </u><u> </u><u> </u><u> </u>4

=<u>4</u><u>(</u><u>2</u><u>x</u><u>+</u><u>y</u><u>)</u>

<u> </u><u> </u> 4

=2x+y

with this, you will understand the following

21. <u>4</u><u>x</u> + <u>8</u><u>y</u>

x+2y x+2y

=<u>4</u><u>x</u><u>+</u><u>8</u><u>y</u>

x+2y

=<u>4(x+2y)</u>

x+2y

=4

22. <u>2</u><u>x</u><u>-</u><u>y</u><u> </u>+ <u>2</u><u>x</u><u>+</u><u>5</u><u>y</u>

4 4

=<u>2</u><u>x</u><u>-</u><u>y</u><u>+</u><u>2</u><u>x</u><u>+</u><u>5</u><u>y</u>

4

=<u>4</u><u>x</u><u>+</u><u>4</u><u>y</u>

4

=<u>4(</u><u>x</u><u>+</u><u>y</u><u>)</u>

4

=x+y

6 0
2 years ago
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