Answer:
Step-by-step explanation:
The only one of these possible answers that could be correct is the fourth one:
The product of a constant factor 5 and a 2-term factor x + 2. That '5' in front of (x+2) multiplies (x+2), and so the result is a product.
Let x be the number of child tickets he bought
Let y be the number of adult tickers he bought
① x+y=7 (child tickets+adult ticket=7 tickets in total)
② 2x+4y=24 (price of child tickets+price of adult tickets=$24 in total)
We may simply the second equation since all of the coefficients are divisible by 2.
① x+y=7
② x+2y=12
We can now use elimination by multiplying the second equation by -1.
② -(x+2y=12)
② -x-2y=-12
① x+y=7
② -x-2y=-12
Now putting the equations together,
-y=-5
y=5
x=2
Therefore he bought 2 child tickets and 5 adult tickets
You can put one rabbit in cell one. Two rabbits in cell two. Three rabbits in cell three. Four rabbits in cell four. Five rabbits in cell five. Six rabbits in cell six. Seven rabbits in cell seven. Eight rabbits in cell eight. And finally nine rabbits in cell nine.
the center is at the origin of a coordinate system and the foci are on the y-axis, then the foci are symmetric about the origin.
The hyperbola focus F1 is 46 feet above the vertex of the parabola and the hyperbola focus F2 is 6 ft above the parabola's vertex. Then the distance F1F2 is 46-6=40 ft.
In terms of hyperbola, F1F2=2c, c=20.
The vertex of the hyperba is 2 ft below focus F1, then in terms of hyperbola c-a=2 and a=c-2=18 ft.
Use formula c^2=a^2+b^2c
2
=a
2
+b
2
to find b:
\begin{gathered} (20)^2=(18)^2+b^2,\\ b^2=400-324=76 \end{gathered}
(20)
2
=(18)
2
+b
2
,
b
2
=400−324=76
.
The branches of hyperbola go in y-direction, so the equation of hyperbola is
\dfrac{y^2}{b^2}- \dfrac{x^2}{a^2}=1
b
2
y
2
−
a
2
x
2
=1 .
Substitute a and b:
\dfrac{y^2}{76}- \dfrac{x^2}{324}=1
76
y
2
−
324
x
2
=1 .
