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PolarNik [594]
2 years ago
8

In Jeremiah class

Mathematics
1 answer:
Irina18 [472]2 years ago
6 0
Answer:

2/5 = 4/10

4/10 = 40%

Explanation:

2/5 is a simplified fraction, and one of the bigger fractions it’s made by 4/10. Do you can use 4/10, but can also use 8/20, 20/50, 40/100, so on. Since we know that any fraction that of ten can be turned into a percentage easily (2/10=20%, 5/10=50%,9/10=%90), then 4/10 is equal to 40%. So 40% of the people in Jeremiah’s class are boys.
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3 years ago
How do you solve 3/5×4 1/6?
Helen [10]
\frac{3}{5} × 4 \frac{1}{6}

First, convert 4\frac{1}{6} to an improper fraction. Use this rule: a \frac{b}{c} = \frac{ac+b}{c} / Your problem should look like: \frac{3}{5} × \frac{4x6+1}{6}
Second, simplify 4 × 6 to 24. / Your problem should look like: \frac{3}{5} × \frac{24+1}{6} 
Third, simplify 24 + 1 to 25. / Your problem should look like: \frac{3}{5} × \frac{25}{6}
Fourth, apply this rule: \frac{a}{b} × \frac{c}{d} = \frac{ac}{bd} / Your problem should look like: \frac{3x25}{5x6}
Fifth, simplify 3 × 25 to 75. / Your problem should look like: \frac{75}{5x6}
Sixth, simplify 5 × 6 to 30. / Your problem should look like: \frac{75}{30}
Seventh, simplify. / Your problem should look like: \frac{5}{2}
Eighth, convert to mixed fraction. / Your problem should look like: 2\frac{1}{2}

Answer: 2 \frac{1}{2}

5 0
3 years ago
Kesha threw her baton up in the air from the marching band platform during practice. The equation h(t) = −16t² + 54t + 40 gives
lapo4ka [179]

Answer:

a) 40 feet

b) 54 ft/min

c) 4 mins

Step-by-step explanation:

Solution:-

- Kesha models the height ( h ) of the baton from the ground level but thrown from a platform of height hi.

- The function h ( t ) is modeled to follow a quadratic - parabolic path mathematically expressed as:

                           h ( t ) = −16t² + 54t + 40

Which gives the height of the baton from ground at time t mins.

- The initial point is of the height of the platform which is at a height of ( hi ) from the ground level.

- So the initial condition is expressed by time = 0 mins, the height of the baton h ( t ) would be:

                         h ( 0 ) = hi = -16*(0)^2 + 54*0 + 40

                         h ( 0 ) = hi = 0 + 0 + 40 = 40 feet

Answer: The height of the platform hi is 40 feet.

- The speed ( v ) during the parabolic path of the baton also varies with time t.

- The function of speed ( v ) with respect to time ( t ) can be determined by taking the derivative of displacement of baton from ground with respect to time t mins.

                        v ( t ) = dh / dt

                        v ( t )= d ( −16t² + 54t + 40 ) / dt

                        v ( t )= -2*(16)*t + 54

                        v ( t )= -32t + 54

- The velocity with which Kesha threw the baton is represented by tim t = 0 mins.

Hence,

                        v ( 0 ) = vi = -32*( 0 ) + 54

                        v ( 0 ) = vi = 54 ft / min

Answer: Kesha threw te baton with an initial speed of vo = 54 ft/min

- The baton reaches is maximum height h_max and comes down when all the kinetic energy is converted to potential energy. The baton starts to come down and cross the platform height hi = 40 feet and hits the ground.

- The height of the ball at ground is zero. Hence,

                     h ( t ) = 0

                     0 = −16t² + 54t + 40

                     0 = -8t^2 + 27t + 20

- Use the quadratic formula to solve the quadratic equation:

                     

                    t = \frac{27+/-\sqrt{27^2 - 4*8*(-20)} }{2*8}\\\\t = \frac{27+/-\sqrt{1369} }{16}\\\\t = \frac{27+/-37 }{16}\\\\t =  \frac{27 + 37}{16} \\\\t = 4

Answer: The time taken for the baton to hit the ground is t = 4 mins

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Step-by-step explanation:

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Answer:

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Step-by-step explanation:

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3 years ago
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