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3 years ago

How many solutions does this system have? x+3y=0 12y=-4x

Mathematics

2 answers:

BabaBlast [244]3 years ago

5 0

Answer:

Step-by-step explanation:

Here you go mate

Step 1

x+3y=0

12y=-4x Equation/Question

Step 2

x+3y=0 Solve for x

x=-3y

Step 3

12y=-4x Substitute -3y for x

12y=12y

Step 4

12y=12y Simplify

0=0

Answer

Infinite solution

Hope this helps

nordsb [41]3 years ago

3 0

I am pretty sure that it has 4 solutions but i’m not 100% positive

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H(x)= ⎩ ⎪ ⎪ ⎪ ⎪ ⎪ ⎪ ⎪ ⎪ ⎨ ⎪ ⎪ ⎪ ⎪ ⎪ ⎪ ⎪ ⎪ ⎧ 8+6x x+4 10 4x−3 , , , x<−7 −7≤x<−5 x≥−5

motikmotik

Answer:

$h(-6) = -\frac{1}{5}$

Step-by-step explanation:

Given

$h(x) =\left[\begin{array}{cc}8 + 6x\ \ &x < -7\\\frac{x + 4}{10} &-7 \le x$

Required

Determine h(-6)

To do this, we make use of:

$h(x) = \frac{x + 4}{10}$

Because $-7 \le -6$

So, we have:

$h(x) = \frac{x + 4}{10}$

$h(-6) = \frac{-6 + 4}{10}$

$h(-6) = \frac{-2}{10}$

Simplify

$h(-6) = -\frac{1}{5}$

4 0

2 years ago

5w = 23 - 3f and 4f = 12 - 2w

Kryger [21]

Answer:

f = 1, w = 4

Step-by-step explanation:

Given the 2 equations

5w = 23 - 3f → (1)

4f = 12 - 2w (add 2w to both sides )

2w + 4f = 12 ( subtract 4f from both sides )

2w = 12 - 4f → (2)

Multiplying (1) by 4 and (2) by - 3 and adding the result will eliminate f

20w = 92 - 12f → (3)

- 6w = - 36 + 12f → (4)

Add (3) and (4) term by term to eliminate f

14w = 56 ( divide both sides by 14 )

w = 4

Substitute w = 4 into either of the 2 equations and solve for f

Substituting into (1)

5(4) = 23 - 3f

20 = 23 - 3f ( subtract 23 from both sides )

- 3 = 3f ( divide both sides by - 3 )

1 = f

5 0

2 years ago

Read 2 more answers

HURRY I WILL GIVE BRAINLIEST which choice is equivalent to the product below √2x√5x√8

Rudik [331]

Answer:

4 radical 5

Step-by-step explanation:

8 0

2 years ago

A recent survey concluded that the proportion of american teenagers who have a cell phone is 0.27. the true population proportio

Jet001 [13]

Answer:

The mean for the sampling distribution of the sample proportion is 0.29

The standard deviation for the sampling distribution of the sample proportion is 0.01435

Step-by-step explanation:

The mean for the sampling distribution of the sample proportion is always equal to the true population proportion, in this case; p = 0.29

The standard deviation for the sampling distribution of the sample proportion is calculated as;

$\sqrt{\frac{p(1-p)}{n} }$

Using the given values;

p = 0.29

1 - p = 0.71

n = 1000

The standard deviation becomes;

$\sqrt{\frac{(0.29)(1-0.29)}{1000} } \\$

The s.d becomes 0.01435

4 0

3 years ago

Directions: Calculate the area of a circle using 3.14x the radius

Leokris [45]

$\qquad\qquad\huge\underline{{\sf Answer}}♨$

As we know ~

Area of the circle is :

$\qquad \sf \dashrightarrow \:\pi {r}^{2}$

And radius (r) = diameter (d) ÷ 2

[ radius of the circle = half the measure of diameter ]

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<h3>Problem 1</h3>

$\qquad \sf \dashrightarrow \:r = d \div 2$

$\qquad \sf \dashrightarrow \:r = 4.4\div 2$

$\qquad \sf \dashrightarrow \:r = 2.2 \: mm$

Now find the Area ~

$\qquad \sf \dashrightarrow \: \pi {r}^{2}$

$\qquad \sf \dashrightarrow \:3.14 \times {(2.2)}^{2}$

$\qquad \sf \dashrightarrow \:3.14 \times {4.84}^{}$

$\qquad \sf \dashrightarrow \:area \approx 15.2 \: \: mm {}^{2}$

・．━━━━━━━†━━━━━━━━━．・

<h3>problem 2</h3>

$\qquad \sf \dashrightarrow \:r = d \div 2$

$\qquad \sf \dashrightarrow \:r = 3.7 \div 2$

$\qquad \sf \dashrightarrow \:r = 1.85 \: \: cm$

Bow, calculate the Area ~

$\qquad \sf \dashrightarrow \: \pi {r}^{2}$

$\qquad \sf \dashrightarrow \:3.14 \times (1.85) {}^{2}$

$\qquad \sf \dashrightarrow \:3.14 \times 3.4225 {}^{}$

$\qquad \sf \dashrightarrow \:area \approx 10.75 \: \: cm {}^{2}$

・．━━━━━━━†━━━━━━━━━．・

<h3>Problem 3 </h3>

$\qquad \sf \dashrightarrow \:\pi {r}^{2}$

$\qquad \sf \dashrightarrow \:3.14 \times (8.3) {}^{2}$

$\qquad \sf \dashrightarrow \:3.14 \times 68.89$

$\qquad \sf \dashrightarrow \:area \approx216.31 \: \: cm {}^{2}$

・．━━━━━━━†━━━━━━━━━．・

<h3>Problem 4</h3>

$\qquad \sf \dashrightarrow \:r = d \div 2$

$\qquad \sf \dashrightarrow \:r = 5.8 \div 2$

$\qquad \sf \dashrightarrow \:r = 2.9 \: \: yd$

now, let's calculate area ~

$\qquad \sf \dashrightarrow \:3.14 \times {(2.9)}^{2}$

$\qquad \sf \dashrightarrow \:3.14 \times 8.41$

$\qquad \sf \dashrightarrow \:area \approx26.41 \: \: yd {}^{2}$

・．━━━━━━━†━━━━━━━━━．・

<h3>problem 5</h3>

$\qquad \sf \dashrightarrow \:r = d \div 2$

$\qquad \sf \dashrightarrow \:r = 1 \div 2$

$\qquad \sf \dashrightarrow \:r = 0.5 \: \: yd$

Now, let's calculate area ~

$\qquad \sf \dashrightarrow \:\pi {r}^{2}$

$\qquad \sf \dashrightarrow \:3.14 \times (0.5) {}^{2}$

$\qquad \sf \dashrightarrow \:3.14 \times 0.25$

$\qquad \sf \dashrightarrow \:area \approx0.785 \: \: yd {}^{2}$

・．━━━━━━━†━━━━━━━━━．・

<h3>problem 6</h3>

$\qquad \sf \dashrightarrow \:\pi {r}^{2}$

$\qquad \sf \dashrightarrow \:3.14 \times {(8)}^{2}$

$\qquad \sf \dashrightarrow \:3.14 \times 64$

$\qquad \sf \dashrightarrow \:area = 200.96 \: \: yd {}^{2}$

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8 0

2 years ago