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alexandr402 [8]
2 years ago
7

What is a fitted value for a multiple regression model and the data that is used to create it?

Mathematics
1 answer:
densk [106]2 years ago
4 0

Fitted value is a prediction of the mean response value.

According to the statement

we have to explain the fitted value for the regression model and the data which uses to collect the value.

So, For this purpose, we know that the  

A Fitted value is a statistical model's prediction of the mean response value when you input the values of the predictors, factor levels, or components into the model.

An the fitted value used in this model is called the predicted values of response variable in the case of multiple regression model.

And data which is used to create the fitted value is the simple data by which we create the fitted value by the predict the value of given data.

So, Fitted value is a prediction of the mean response value.

Learn more about Fitted value here

brainly.com/question/6592115

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a school has 2 computer labs.Each lab has 30 computers. A total of 6 computers in the school are not working. which experission
jasenka [17]

Answer:

30(2)-6

Step-by-step explanation:

30 computers in 2 labs minus the 6 broken computers.

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8. Jack is going to paint the ceiling and four
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Answer:

D

Step-by-step explanation:

7 0
3 years ago
Merry Soy, married, earns a weekly salary of $830 and claims one withholding allowance. By the percentage method, how much incom
xxMikexx [17]
You need to find the amount subject to withholding, subtracting from the weekly salary the amount for one withholding allowance for weekly salaries, which is 77.90$:

830 - 77.90 = 752.1 $.

Then, look in the Fed Tax tables (
http://www.opers.ok.gov/Websites/opers/images/pdfs/2016-Fed-Tax-Tables.pdf ) for a married person with a weekly payroll.

You previously found an amount of  752.1 which is greater than 521 but less than 1613$: therefore the income tax to withhold is 35.70$ + 15% of excess over $521.

Therefore, calculate the income tax due: 35.70 + (752.1 - 521) × 15 ÷ 100 = 70.37$

The total amount of income tax that will be withheld is 70.37$
4 0
3 years ago
The mean points obtained in an aptitude examination is 159 points with a standard deviation of 13 points. What is the probabilit
Korolek [52]

Answer:

0.4514 = 45.14% probability that the mean of the sample would differ from the population mean by less than 1 point if 60 exams are sampled

Step-by-step explanation:

To solve this question, we have to understand the normal probability distribution and the central limit theorem.

Normal probability distribution:

Problems of normally distributed samples are solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

Central limit theorem:

The Central Limit Theorem estabilishes that, for a random variable X, with mean \mu and standard deviation \sigma, a large sample size can be approximated to a normal distribution with mean \mu and standard deviation s = \frac{\sigma}{\sqrt{n}}

In this problem, we have that:

\mu = 159, \sigma = 13, n = 60, s = \frac{13}{\sqrt{60}} = 1.68

What is the probability that the mean of the sample would differ from the population mean by less than 1 point if 60 exams are sampled?

This is the pvalue of Z when X = 159+1 = 160 subtracted by the pvalue of Z when X = 159-1 = 158. So

X = 160

Z = \frac{X - \mu}{\sigma}

By the Central Limit Theorem

Z = \frac{X - \mu}{s}

Z = \frac{160 - 159}{1.68}

Z = 0.6

Z = 0.6 has a pvalue of 0.7257

X = 150

Z = \frac{X - \mu}{s}

Z = \frac{158 - 159}{1.68}

Z = -0.6

Z = -0.6 has a pvalue of 0.2743

0.7257 - 0.2743 = 0.4514

0.4514 = 45.14% probability that the mean of the sample would differ from the population mean by less than 1 point if 60 exams are sampled

7 0
3 years ago
PLEASE HELP!!
SIZIF [17.4K]

(x, y)

Domain = x

Range = y

It is a function when none of the x values are repeating.

Answer - C) Both A and B

Hope this helps and makes sense!!

8 0
3 years ago
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