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3 years ago

The sum of three consecutive odd integers is 153. Find the three odd integers.

Mathematics

1 answer:

igomit [66]3 years ago

6 0

The answer is 50,51 and 52

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Find the distance between the two points in simplest radical form.

sweet-ann [11.9K]

Answer:

3 $\sqrt{13}$

Step-by-step explanation:

Calculate the distance using the distance formula

d = $\sqrt{(x_{2}-x_{1})^2+(y_{2}-y_{1})^2 }$

with (x₁, y₁ ) = (- 9, 8) and (x₂, y₂ ) = (- 3, - 1)

d = $\sqrt{(-3-(-9))^2+(-1-8)^2}$

= $\sqrt{(-3+9)^2+(-9)^2}$

= $\sqrt{6^2+81}$

= $\sqrt{36+81}$

= $\sqrt{117}$

= $\sqrt{9(13)}$

= $\sqrt{9}$ × $\sqrt{13}$

= 3 $\sqrt{13}$

8 0

2 years ago

The cost for a company to produce x t-shirts can be modeled by C(x)=21x-98 and the revenue for selling these shirts can be model

mixer [17]

Answer:

The Answer is C

Step-by-step explanation:

It's C for Apex

5 0

3 years ago

Read 2 more answers

Find the first, fourth, and tenth terms of the arithmetic sequence described by the given rule. A(n)=-6+(n-1)(1/5) A)-6,-5 1/5,

scoundrel [369]

Step-by-step explanation:

An arithmetic sequence is given by relation as follows :

$A(n)=-6+(n-1)\dfrac{1}{5}$

For the first term, put n = 1. So,

$A(1)=-6+(1-1)\dfrac{1}{5}\\\\A(1)=-6$

For fourth term, put n = 4. So,

$A(4)=-6+(4-1)\dfrac{1}{5}\\\\A(4)=\dfrac{-27}{5}\\\\A(4)=-5\dfrac{2}{5}$

For tenth term, put n = 10. So,

$A(10)=-6+(10-1)\dfrac{1}{5}\\\\A(10)=-6+\dfrac{9}{5}\\\\A(10)=\dfrac{-21}{5}\\\\A(10)=-4\dfrac{1}{5}$

Hence, the correct option is (C).

7 0

3 years ago

Need help on this math problem

erik [133]

Answer:

$-5, 18, \sqrt{13}$

Step-by-step explanation:

We can solve the first equation, f of -3. The value of the function f is $\frac{1+x^2}{x+1}$ , and plugging in -3 gets us $\frac{1+9}{1-3}$ , this results in 10 divided by negative 2, which is negative 5.

Now, we must solve g of negative one third. The function g is defined as $|9x-15|$ . Plugging in negative one third into the question gets us $|9(-\frac{1}{3})-15|$

9 times negative one third is -3, and -3 minus 15 is -18. The absolute value of -18 is 18.

Now, we must solve h of negative 2, and h is defined as $\sqrt{-3-8x}$ . Plugging in negative 2, we have $\sqrt{-3-8(-2)}$ . Negative 8 times negative 2 is positive 16, and 16 minus 3 is 13. The answer is the square root of 13

7 0

2 years ago

Michael sold his painting for $50. He sold his painting for $10 less than its original price. At what price did Michael buy the

netineya [11]

It would be 60. He sold his painting for 50 which was 10 less that the original price. So 50+10=60

7 0

3 years ago

Read 2 more answers