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Mazyrski [523]
2 years ago
13

Find the coordinates of the missing endpoint if B is the midpoint of

Mathematics
1 answer:
Zarrin [17]2 years ago
3 0

The coordinates of the missing endpoint are A(x, y) = (1, 6).

<h3>What is the missing end of the line segment?</h3>

In this problem we know the locations of one end of the line segment and the midpoint and the location of the missing end has to be found by means of the vectorial form of the midpoint formula:

0.5 · A(x, y) + 0.5 · C(x, y) = B(x, y)

0.5 · A(x, y) = B(x, y) - 0.5 · C(x, y)

A(x, y) = 2 · B(x, y) - C(x, y)

If we know that B(x, y) = (- 2, 5) and C(x, y) = (- 5, 4), then the location of the missing end is:

A(x, y) = 2 · (- 2, 5) - (- 5, 4)

A(x, y) = (- 4, 10) + (5, - 4)

A(x, y) = (1, 6)

The coordinates of the missing endpoint are A(x, y) = (1, 6).

To learn more on midpoints: brainly.com/question/28224145

#SPJ1

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What is the y-coordinate of the point that divides the directed
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(D)5

Step-by-step explanation:

Given the point J(-3,1) and K(8,11).

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In the given case:

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\dfrac{my_2+ny_1}{m+n}=\dfrac{2*11+3*1}{3+2}\\\\=\dfrac{22+3}{5}\\\\=\dfrac{25}{5}\\\\=5

The y-coordinate of the point that divides the directed  line segment from J to K into a ratio of 2:3 is 5.

The correct option is D.

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