Answer:
The 99% (two-sided) confidence interval for the true average echo duration μ is between 0 sec and 1.99 sec.
Step-by-step explanation:
We have the sample standard deviation, so we use the student t-distribution to solve this question.
The first step to solve this problem is finding how many degrees of freedom, we have. This is the sample size subtracted by 1. So
df = 101 - 1 = 100
99% confidence interval
Now, we have to find a value of T, which is found looking at the t table, with 100 degrees of freedom(y-axis) and a confidence level of [tex]1 - \frac{1 - 0.99}{2} = 0.995. So we have T = 2.6259
The margin of error is:
M = T*s = 2.6259*0.45 = 1.18
In which s is the standard deviation of the sample.
The lower end of the interval is the sample mean subtracted by M. So it is 0.81 - 1.18. Answer in seconds cannot be negative, so we use 0 sec.
The upper end of the interval is the sample mean added to M. So it is 0.81 + 1.18 = 1.99 sec
The 99% (two-sided) confidence interval for the true average echo duration μ is between 0 sec and 1.99 sec.
Answer:

Step-by-step explanation:
Given


Required
Determine the ratio of lawns in spring to total


Convert to fraction


<em>Hence, the ratio of lawns sold in spring to the total is 0.7</em>
Since the person didn't write the answer choices they were:
A. On average, city A was warmer than city B.
B. The median and mode are different for city B.
C. The temperature range between the maximum and minimum values for city A is greater than the temperature range between the maximum and minimum values for city B.
D. The median is less for city A than for city B.
I believe it is A personally cause i took the test and got it right
Your answer is c, an obtuse triangle because if the two side lengths are the same length along with a longer side, it become obtuse
let me know if you have any other questions
:)
Answer:
T = 0.34r³
Step-by-step explanation:
Given that T is directly proportional to r³ then the equation relating them is
T = kr³ ← k is the constant of variation
To find k use the condition T = 21.76 when r = 4 , then
21.76 = k × 4³ = 64k ( divide both sides by 64 )
0.34 = k
T= 0.34r³ ← equation of variation