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3 years ago

A stack of books is 35 inches high. If each book is 1 3/4 inches thick, how many books are in the stack?

Mathematics

1 answer:

boyakko [2]3 years ago

8 0

Answer:

20 books

Step-by-step explanation:

Height of stack = 35 inches

Thickness of one book $=1\frac{3}{4} =\frac{7}{4}\: in$

No. of books

$= 35 \div \frac{7}{4} \\ \\ = 35 \times \frac{4}{7} \\ \\ = 5 \times 4 \\ \\ = 20$

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4 years ago

An internet search engine looks for a certain keyword in a sequence of independent web sites. It is believed that 20% of the sit

marusya05 [52]

Answer:

(a) The probability that at least 5 of the first 10 sites contain the given keyword is 0.0328.

(b) The probability that the search engine had to visit at least 5 sites in order to find the first occurrence of a keyword is 0.4096.

Step-by-step explanation:

(a)

Let X = number of sites that contains the keyword.

The probability that a site contains the keyword is, p = 0.20.

The number of sites visited first is n = 10.

The random variable X follows a Binomial distribution with parameter n and p.

The probability mass function of X is:

$P(X=x)={10\choose x}0.20^{x}(1-0.20)^{10-x};\ x=0,1,2,3...$

Compute the probability that at least 5 of the first 10 sites contain the given keyword as follows:

P (X ≥ 5) = 1 - P (X < 5)

= 1 - P (X = 0) - P (X = 1) - P (X = 2) - P (X = 3) - P (X = 4)

$=1-\sum\limits^{4}_{x=0} {10\choose x}0.20^{x}(1-0.20)^{10-x}\\=1-0.1074-0.2684-0.3020-0.2013-0.0881\\=0.0328$

Thus, the probability that at least 5 of the first 10 sites contain the given keyword is 0.0328.

(b)

Let Y = number of sites that contains the keyword.

The probability that a site contains the keyword is, p = 0.20.

The random variable Y follows a Geometric distribution with parameter p.

The probability mass function of Y is:

$P(Y=y)=(1-p)^{x-1}p;\ x=1,2,3...$

Compute the probability that the search engine had to visit at least 5 sites in order to find the first occurrence of a keyword as follows:

P (X ≥ 5) = 1 - P (X ≤ 4)

$=1-\sum\limits^{4}_{x=1} (1-0.20)^{x-1}0.20\\=1-0.20-0.16-0.128-0.1024\\=0.4096$

Thus, the probability that the search engine had to visit at least 5 sites in order to find the first occurrence of a keyword is 0.4096.

4 0

4 years ago