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USPshnik [31]
3 years ago
7

I need help with 8 i don't understand it i get. idk how to figure out what jm is

Mathematics
1 answer:
Misha Larkins [42]3 years ago
8 0
The segment bisector of line JK would be L since it passes through M
How to find JM is that you would have to solve 3x+15=8x+25 to get x and once you find x you just plug it into the equation for JM, 3x+15
3x+15=8x+25 (subtract 8x on both sides)
-5x+15=25 (subtract 15 on both sides)
-5x=10 (Divide on both sides)
x=-2
Plug that in:
3(-2)+15
-6+15
JM=9
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see explanation

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The cosine function in standard form is

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3 years ago
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atroni [7]

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5 0
3 years ago
<img src="https://tex.z-dn.net/?f=%5Csqrt%5B3%5D%7B-8%2F27%7D%20%3D%20-2%2F3" id="TexFormula1" title="\sqrt[3]{-8/27} = -2/3" al
sasho [114]
The equation is true because both sides are identical.
5 0
3 years ago
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