I just did this test the answer is B :-)
Answer:
A two-digit number can be written as:
a*10 + b*1
Where a and b are single-digit numbers, and a ≠ 0.
We know that:
"The sum of a two-digit number and the number obtained by interchanging the digits is 132."
then:
a*10 + b*1 + (b*10 + a*1) = 132
And we also know that the digits differ by 2.
then:
a = b + 2
or
a = b - 2
So let's solve this:
We start with the equation:
a*10 + b*1 + (b*10 + a*1) = 132
(a*10 + a) + (b*10 + b) = 132
a*11 + b*11 = 132
(a + b)*11 = 132
(a + b) = 132/11 = 12
Then:
a + b = 12
And remember that:
a = b + 2
or
a = b - 2
Then if we select the first one, we get:
a + b = 12
(b + 2) + b = 12
2*b + 2 = 12
2*b = 12 -2 = 10
b = 10/2 = 5
b = 5
then a = b + 2= 5 + 2 = 7
The number is 75.
And if we selected:
a = b - 2, we would get the number 57.
Both are valid solutions because we are changing the order of the digits, so is the same:
75 + 57
than
57 + 75.
Answer:
x = 1
Step-by-step explanation:
There are a couple of ways to solve this. One is to graph the left side of the equation, graph the right side of the equation, and look for the point where those graphs intersect. It is at x = 1. The first attached graph shows this solution.
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Another method for solving such an equation is to subtract one side from the other and look for the value of x that makes the resulting expression zero.
(-2x +3) -(-3(-x) -2) = 0
A graphing calculator doesn't need to have this simplified. If it is simplified, it becomes ...
-5x +5 = 0
So, the graphed line is y = -5x+5. Its x-intercept is x=1, the solution of the original equation. The graph of this is shown in the second attachment.
Given:
64 total students
x = drama club students
y = yearbook club students
x = y + 10
y = 64 - x
y = 64 - x
y = 64 - (y + 10)
y = 64 - y - 10
y + y = 64 - 10
2y = 54
2y/2 = 54/2
y = 27
x = y + 10
x = 27 + 10
x = 37
To check:
x + y = 64
37 + 27 = 64
64 = 64
