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3 years ago

Helllpppppp it’s due tomorrow plssss

Mathematics

2 answers:

Helen [10]3 years ago

8 0

Answer:

A-B= 1/4 inch

A-G= 3-3/4 inch

A-D= 3/4 inch

A-K= 4-3/4 inch

A-I= 1-3/4 inch

A-E 1 inch

A-J= 3 inch

A-L= 4-1/4 inch

A-F= 2-1/4 inch

A-H= 1-1/2 inch

A-C= 1/2 inch

A-M= 5-3/4 inch

Step-by-step explanation:

elena-14-01-66 [18.8K]3 years ago

4 0

A to B = 0.25 (a quarter or 1/4)
A to G = 3.75 (3 3/4)
A to D = 0.75 (3/4)
A to K = 4.75 (4 3/4)
A to I = 1.75 (1 3/4)
A to E = 1
A to J = 3
A to L = 4.25 (4 1/4)
A to F = 2.25 (2 1/4)
A to H = 1.50 (1 1/2)
A to C = 0.5 (1/2)
A to M = 5.75 (5 3/4)

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What is -5 5/8 + 3 1/2? Answer now for 25 points and a brainly!

Viefleur [7K]

<h3>Answer: Choice C) -2 & 1/8</h3>

==============================================

Work Shown:

5 & 5/8 = 5 + 5/8

-5 & 5/8 = -(5 & 5/8) = -(5 + 5/8) = -5 - 5/8

So,

( -5 & 5/8 ) + ( 3 & 1/2 )

( -5 - 5/8 ) + ( 3 + 4/8 )

( -5+3 ) + ( -5/8+4/8 )

-2 + (-1/8)

-(2 + 1/8)

-(2 & 1/8)

-2 & 1/8

------------------------

Alternative Method

We could convert each mixed number to decimal form

-5 & 5/8 = -5-5/8 = -5.625

3 & 1/2 = 3+1/2 = 3.5

( -5 & 5/8 ) + ( 3 & 1/2 ) = -5.625+3.5 = -2.125

Then convert back to mixed number form

-2.125 = -2 & 125/1000

-2.125 = -2 & (1*125)/(8*125)

-2.125 = -2 & 1/8

6 0

3 years ago

Evacuate 9-b when b-8

MakcuM [25]

9-b when b=8

9 -8 =1

9-b when b=-8

9 - (-8)

9+8

I'm not sure whether you meant b=8 or b=-8

4 0

3 years ago

The position function of a particle in rectilinear motion is given by s(t) = 2t3 – 21t2 + 60t + 3 for t ≥ 0 with t measured in s

Norma-Jean [14]

The positions when the particle reverses direction are:

$s(t_1)=55ft\\\\s(t_2)=28ft$

The acceleraton of the paticle when reverses direction is:

$a(t_1)=-18\frac{ft}{s^{2}}\\ \\a(t_2)=a(5s)=18\frac{ft}{s^{2}}$

Why?

To solve the problem, we need to remember that if we derivate the position function, we will get the velocity function, and if we derivate the velocity function, we will get the acceleration function. So, we will need to derivate two times.

Also, when the particle reverses its direction, the velocity is equal to 0.

We are given the following function:

$s(t)=2t^{3}-21t^{2}+60t+3$

So,

- Derivating to get the velocity function, we have:

$v(t)=\frac{ds}{dt}=(2t^{3}-21t^{2}+60t+3)\\\\v(t)=3*2t^{2}-2*21t+60*1+0\\\\v(t)=6t^{2}-42t+60$

Now, making the function equal to 0, to find the times when the particle reversed its direction, we have:

$v(t)=6t^{2}-42t+60\\\\0=6t^{2}-42t+60\\\\0=t^{2}-7t+10\\(t-5)*(t-2)=0\\\\t_{1}=5s\\t_{2}=2s$

We know that the particle reversed its direction two times.

- Derivating the velocity function to find the acceleration function, we have:

$a(t)=\frac{dv}{dt}=6t^{2}-42t+60\\\\a(t)=12t-42$

Now, substituting the times to calculate the accelerations, we have:

$a(t_1)=a(2s)=12*2-42=-18\frac{ft}{s^{2}}\\ \\a(t_2)=a(5s)=12*5-42=18\frac{ft}{s^{2}}$

Now, substitutitng the times to calculate the positions, we have:

$s(t_1)=2*(2)^{3}-21*(2)^{2}+60*2+3=16-84+120+3=55ft\\\\s(t_2)=2*(5)^{3}-21*(5)^{2}+60*5+3=250-525+300+3=28ft$

Have a nice day!

3 0

3 years ago

Please help me out with this i only have a couple more hours to turn this in please

Alborosie

Answer:

H = (1,4)

I = (-4,2)

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3 years ago

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Solve the linear equation by using the Gauss-Jordan elimination method

Paha777 [63]

Answer: ( x , − x/ 3 − 5 /3 )

Step-by-step explanation:

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4 years ago