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jok3333 [9.3K]
3 years ago
8

Can Anyone help me out?

Mathematics
2 answers:
Andreas93 [3]3 years ago
5 0
The answer is A.
It is a translation 4 units to the right, and such is A.
Y_Kistochka [10]3 years ago
3 0

g(x) = \sqrt[3]{(x-4)}

given g(x) = f(x) then f(x - 4 ) represents a translation of 4 units to the right

while f(x + 4) represents a translation of 4 units to the left

the graph of y = \sqrt[3]{x} passes through the origin and since

the graph of the translation passes through (4, 0 ), thus

g(x) = \sqrt[3]{(x-4)}





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The football team has a total of 350 jersey there are 150 medium-sized-jersey. Percent of jerseys are medium-sized-jerseys
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A sequence is defined by the recursive function f(n+1)= f(n) -2. If f(1) =10. what is f(3)?
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(\stackrel{x_1}{6}~,~\stackrel{y_1}{0})\qquad (\stackrel{x_2}{3}~,~\stackrel{y_2}{2}) ~\hfill \stackrel{slope}{m}\implies \cfrac{\stackrel{rise} {\stackrel{y_2}{2}-\stackrel{y1}{0}}}{\underset{run} {\underset{x_2}{3}-\underset{x_1}{6}}}\implies \cfrac{2}{-3}\implies -\cfrac{2}{3} \\\\\\ \begin{array}{|c|ll} \cline{1-1} \textit{point-slope form}\\ \cline{1-1} \\ y-y_1=m(x-x_1) \\\\ \cline{1-1} \end{array}\implies y-\stackrel{y_1}{0}=\stackrel{m}{-\cfrac{2}{3}}(x-\stackrel{x_1}{6})

\stackrel{\textit{multiplying both sides by }\stackrel{LCD}{3}}{3(y-0)~~ = ~~3\left( -\cfrac{2}{3}(x-6) \right)}\implies 3y=-2(x-6) \\\\\\ 3y=-2x+12 \implies \stackrel{a}{2} x+\stackrel{b}{3} y=12

5 0
2 years ago
Please help me with #2! Thanks!!!
Tanya [424]
The answer is B because the inverse of a squared number is the square root.
7 0
3 years ago
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