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Ymorist [56]
3 years ago
13

Solve the system of linear equations by elimination.

Mathematics
2 answers:
Leona [35]3 years ago
6 0
The first x is 2 and the second x is 2,1
lilavasa [31]3 years ago
4 0
   x+y=3
+ x-y=1
2x=4
x=2

x+y=3
2+y=3
-2.   -2
y=1

(2,1)
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A certain relationship is defined as having only one corresponding y-value for each x-value. Which of the following best describ
igomit [66]

Answer:

We conclude that a function is defined as having only one corresponding y-value for each x-value.

Hence, option (C) is true.

Step-by-step explanation:

We know that A function is a certain relationship is defined as having only one corresponding y-value for each x-value.

Considering the function

  • f(x) = x+1

Here,

  • x is the input and f(x) or y is the output.
  • 'x' is often called an independent value and y is called the 'dependent' value.

Considering the table

x                      y

1                      2

2                     3

3                     4

4                     5

The values in the table satisfy the function y = x+1.

It is clear from the table that the function has only one corresponding y-value for each x-value. In other words, there is no repetition of 'x' value.

Therefore, we conclude that a function is defined as having only one corresponding y-value for each x-value.

Hence, option (C) is true.

6 0
3 years ago
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posledela
314 m is the correct answer.
3 0
3 years ago
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What is the average rate of change of f over the interval -1 on a separate sheet of paper and upload the work as a photo. Show a
Anarel [89]

Answer:

Average rate of change for the function f(x)= x^2-x-1 over the interval -1<x<1 is -1

Step-by-step explanation:

We need to find average rate of change of f over the interval -1 < x < 1

The function given is: f(x)= x^2-x-1

The formula used to find average rate of change is:

Average\:rate\:of\:change=\frac{f(b)-f(a)}{b-a}

We have, a = -1 and b = 1

Finding f(b) when b=1

f(x)=x^2-x-1\\f(1)=(1)^2-(1)-1\\f(1)=1-1-1\\f(1)=-1

Now, finding f(a), when a= -1

f(x)=x^2-x-1\\f(-1)=(-1)^2-(-1)-1\\f(1)=1+1-1\\f(-1)=2-1\\f(-1)=1

Now, putting values and finding average rate of change

Average\:rate\:of\:change=\frac{f(b)-f(a)}{b-a}\\Average\:rate\:of\:change=\frac{f(1)-f(-1)}{1-(-1)}\\Average\:rate\:of\:change=\frac{-1-(1)}{1-(-1)}\\Average\:rate\:of\:change=\frac{-1-1}{1+1}\\Average\:rate\:of\:change=\frac{-2}{2}\\Average\:rate\:of\:change=-1

So, average rate of change for the function f(x)= x^2-x-1 over the interval -1<x<1 is -1

4 0
3 years ago
Apparently I cant simplify
Mashcka [7]

Answer: 3a

Step-by-step explanation:

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Answer: have you found the answer yet????

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