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3 years ago

Select all possible values for x that solve the equation x^2=800

Mathematics

1 answer:

Gemiola [76]3 years ago

6 0

x^2 = 800. Take the square root of each side.

x = √(800) and -√(800)

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Can someone please help me? I don't understand this problem. How would they be the same???

musickatia [10]

Area of rectangle = 15 x 8
=120

area of parallelogram = 8 x 15
=120
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3 years ago

Which is equivalent sin^-1 (cos(pi/2))?Give your answer in radians

NNADVOKAT [17]

Answer:

Given the expression: $\sin^{-1}(\cos(\frac{\pi}{2}))$

Let the value of the given expression in radians be $\theta$

then;

$\sin^{-1}(\cos(\frac{\pi}{2})) =\theta$

$\cos \frac{\pi}{2} = \sin \theta$ ......[1]

We know the value of $\cos \frac{\pi}{2} = 0$

Substitute the given value in [1] we have;

$\sin \theta = 0$

Since, the value of $\sin \theta$ is 0, therefore, the value of $\theta$ is in the form of:

$\theta = n\pi$ ; where n is the integer.

At n =0, 1 and 2, {Since, n is the integer}

Value of $\theta =0, \pi$ and $2\pi$

therefore, the answer in radians either $0 , \pi$ or $2\pi$

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3 years ago

Read 2 more answers

The equation of a circle is given below. Identify the center and radius. Then graph the circle.

Blizzard [7]

Answer:

Center = (3, 0)
Radius = 3
Graph = see below

Concept:

Here, we need to know the idea of the circle equation.

Circle equation: (x - h)² + (y - k)² = r²

(h, k) = center

r = radius

x = variable

y = variable

Solve:

Given expression

(x - 3)² + y² = 9

Find the point of the center

(h, k) = $\boxed{(3,0)}$

Find the length of the radius

r² = 9

$\boxed{r=3}$

Hope this helps!! :)

Please let me know if you have any questions

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3 years ago

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Anuta_ua [19.1K]

Answer:

When graphing a linear inequality on a number line, use an open circle for "less than" or "greater than", and a closed circle for "less than or equal to" or "greater than or equal to".

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2 years ago

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Please round to the nearest tenth if possible.

Butoxors [25]

$\bf \cfrac{64~\underline{mi}}{\underline{hr}}\cdot \cfrac{\underline{hr}}{60~sec}\cdot \cfrac{5200~ft}{\underline{mi}}\implies \cfrac{64\cdot 5200~ft}{60~sec}\implies \cfrac{16640~ft}{3~sec}
\\\\\\
\approx 5546.67\frac{ft}{sec}\\\\
-------------------------------\\\\
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$\bf -------------------------------\\\\
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4 years ago