Answer:
m=4 is the correct answer
Answer:
a rectangle is twice as long as it is wide . if both its dimensions are increased 4 m , its area is increaed by 88 m squared make a sketch and find its original dimensions of the original rectangle
Step-by-step explanation:
Let l = the original length of the original rectangle
Let w = the original width of the original rectangle
From the description of the problem, we can construct the following two equations
l=2*w (Equation #1)
(l+4)*(w+4)=l*w+88 (Equation #2)
Substitute equation #1 into equation #2
(2w+4)*(w+4)=(2w*w)+88
2w^2+4w+8w+16=2w^2+88
collect like terms on the same side of the equation
2w^2+2w^2 +12w+16-88=0
4w^2+12w-72=0
Since 4 is afactor of each term, divide both sides of the equation by 4
w^2+3w-18=0
The quadratic equation can be factored into (w+6)*(w-3)=0
Therefore w=-6 or w=3
w=-6 can be rejected because the length of a rectangle can't be negative so
w=3 and from equation #1 l=2*w=2*3=6
I hope that this helps. The difficult part of the problem probably was to construct equation #1 and to factor the equation after performing all of the arithmetic operations.
Answer:
-3.3>-10/3
Step-by-step explanation:
-10.3 is equal to -3.3333333333....
-3.3 just stops at the tenths so there is 0.033333333 more in -10/3. The higher the negative number the lower it is, for example -3>-4. Therefore, -3.3>-10/3.
Answer:
84
Step-by-step explanation:
Combinations
nCr
n (objects) = 9
r (sample) = 3
9C3
n! / r! (n – r)!
9! / 3! (9 – 3)!=
9! / (3! * 6!)=
9*8*7*6!/ (3! * 6!)=
6! cancels out
9*8*7/3*2*1=
3*4*7=
12*7=
84
