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Question 2 of 5

Answer 1

The surface area of the pyramid is 18,541 mm² . Option C

How to determine the surface area

The formula for surface area of a regular hexagonal prism is expressed as;

$A =\frac{3\sqrt{3} }{2} a^2 + 3a\sqrt{h^2+\frac{3a^2}{4} }$

Where;

• a is the edge length = 44 millimeters
• h is the height = 95 millimeters

A = 2. 598 ( 44)² + 3(44) $\sqrt{(95)^2+\frac{3(44)^2}{4} }$

Simplify

A = 5029. 728 + 132 $\sqrt{10477}$

Find the square root

A = 5029. 728 + 132(102. 357)

expand the bracket

A = 5029. 728 + 13511. 124

A = 18, 540. 85

A =  18,541 mm² in thee nearest square millimeter

Thus, the surface area of the pyramid is 18,541 mm² . Option C

Learn more about surface area here:

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