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3 years ago

Please help I’m being timed

Mathematics

1 answer:

olasank [31]3 years ago

4 0

Answer: D: x ∈ [0, 4)

Step-by-step explanation:

For a function:

y = f(x)

The range is the set of the outputs, the possible "y" values

The domain is the set of the inputs, the possible "x" values.

Now, we want to see the domain in which the function increases.

First, we can see that the whole domain of the graph is the interval:

[0, 9]

And a function is increasing if, reading from left to righ, the graph goes upwards.

In the image, we can see that the graph increases in the segment:

[0, 4)

Where we have an open segment because in the point x = 4 the graph stops increasing.

Then the domain where the function increases is:

D: x ∈ [0, 4)

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Students were asked to choose their favorite cafeteria lunch. The results were: pizza, chicken, chicken, taco, taco, pizza, taco

wariber [46]

Pizza- 6, Chicken- 2, Taco- 5, Burger- 2. Pizza should be your answer.

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3 years ago

Ryan buys a bag of cookies that contains 8 chocolate chip cookies, 4 peanut butter cookies, 4 sugar

Pavlova-9 [17]

Answer:

4/69 to be exact. Slightly greater than 1/18

Step-by-step explanation:

The chance of selecting the PB cookie on the first try is 4 out of 24 or 1 out of 6. There are now 23 coolies left; 8 are chocolate, so 8/23 chance. (Slightly greater than 1/3) The chance of both events happening is the product if the individual events' chances. So multiply 1/6 times 8/23 to get 8/138. That reduces to 4/ 69. If he had put that first cookie back, the multiplication would have been 1/6×1/3. A lot easier.

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3 years ago

Three vertices of a square are given. Find the coordinates of the fourth vertex. (_5, 5), (_5, 2), (_2, 2)

Katena32 [7]

<span>If you plot these points, you can probably see where the missing square corner is. But you might also notice that a square's sides are equal length. Between the first two coordinate pairs, the only thing that changes is the y value, from 5 to 2, or a change of 3. Between the 2nd two coordinate pairs, only the x value changes, from -5 to -2, or a change of 3. So it looks like the sides are 3 units long. The fourth coordinate should be 3 units away on the x coordinate from one "neighbor" and 3 units away on the y coordinate from its other neighbor. But it really would help to sketch it out so you don't get mixed up.
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3 years ago

The number of defects in the first five cars to come through a new production line are 9, 7, 10, 4, and 6, respectively. If the

garri49 [273]

Answer:

D. I and III only

Step-by-step explanation:

Number of first fie defects are given as 9,7,10,4 and 6.

First we have to arrange the above data in ascending order which is 4,6,7,9,10

Now if we consider the defect in sixth car to be 3 then our data will look like: 3,4,6,7,9,10

So the mean of above data would be $\frac{3+4+6+7+9+10}{6}$ = 6.5

and Median of the above data would be = $\frac{3^{rd} obs + 4^{th} obs}{2}$ = $\frac{6+7}{2}$ = 6.5

Hence mean and median number of defects are same if the sixth car has 3 defects.

Now if we consider the defect in sixth car to be 12 then our data will look like: 4,6,7,9,10,12

So the mean of above data would be $\frac{4+6+7+9+10+12}{6}$ = 8

and Median of the above data would be = $\frac{3^{rd} obs + 4^{th} obs}{2}$ = $\frac{7+9}{2}$ = 8

Hence mean and median number of defects are same if the sixth car has 12 defects.

But Now if we consider the defect in sixth car to be 7 then our data will look like: 4,6,7,7,9,10

So the mean of above data would be $\frac{4+6+7+7+9+10}{6}$ = 7.167

and Median of the above data would be = $\frac{3^{rd} obs + 4^{th} obs}{2}$ = 7

Hence mean and median number of defects are not same if the sixth car has 7 defects.

Therefore option D is correct.

8 0

3 years ago

Benjamin is trying to find the height of a radio antenna on the roof of a local building.

xz_007 [3.2K]

The height of the antenna on the roof of the local building is approximately 8 meters.

The situation forms a right angle triangle.

<h3>Properties of a right angle triangle:</h3>

One of its angles is equals to 90 degrees
The sides of the triangles can be calculated using Pythagoras theorem.

Therefore, let's find the height of the building and the radio antenna from the eye point.

Using trigonometric ratios,

tan 40° = opposite / adjacent

tan 40° = x / 25

where

x = the height of the building and the radio antenna from the eye point.

x = 25 tan 40

x = 25 × 0.83909963117

x = 20.9774907794 meters

Let's find the height of the building from his eye point.

tan 28° = y / 25

where

y = height of the building from his eye point

y = 25 × tan 28°

y = 25 × 0.53170943166

y = 13.2927357915 meters

Height of the antenna = 20.9774907794 - 13.2927357915 = 7.68475498786

Height of the antenna ≈ 8 meters

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