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Andreas93 [3]
1 year ago
15

Recycled​ CDs, Incorporated, offers a choice of 5 used CDs for ​$27​, with each additional CD costing ​$5. Write a cost function

for purchasing 5 or more CDs. What will the cost of buying 6 CDs​ be? Let x represent the number of CDs over 5.
Mathematics
1 answer:
notka56 [123]1 year ago
8 0

A function assigns the values. The cost of 6 CDs will be $32.

<h3>What is a Function?</h3>

A function assigns the value of each element of one set to the other specific element of another set.

Given that the Recycled​ CDs. Incorporated, offers a choice of 5 used CDs for ​$27​, with each additional CD costing ​$5. Therefore, a cost function for purchasing 5 or more CDs, where x represents the number of CDs over 5 can be written as,

C(x) = $27 + $5(x)

Now, if 6 CDs are purchased then the number of CDs that are more than 5 is 1. therefore, the cost of 6 CDs will be,

C(1) = $27 + $5(1)

     = $27 + $5

     = $32

Hence, the cost of 6 CDs will be $32.

Learn more about Function here:

brainly.com/question/5245372

#SPJ1

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Step-by-step explanation:

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Kisachek [45]
<h3>Answer: D) 5</h3>

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Explanation:

If we plugged x = 3 into the expression, then we'd get x-3 = 3-3 = 0 in the denominator. That's not allowed. But we can simplify first

x^2-x-6 factors to (x-3)(x+2). The key here is that (x-3) is a factor. It cancels with the x-3 in the denominator

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\displaystyle \lim_{x \to 3}\frac{x^2-x-6}{x-3} = \lim_{x \to 3}\frac{(x-3)(x+2)}{x-3}\\\\\\\displaystyle \lim_{x \to 3}\frac{x^2-x-6}{x-3} = \lim_{x \to 3}(x+2)\\\\\\\displaystyle \lim_{x \to 3}\frac{x^2-x-6}{x-3} = 3+2\\\\\\\displaystyle \lim_{x \to 3}\frac{x^2-x-6}{x-3} = 5\\\\\\

5 0
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Tan(2 sin^-1 0.4)<br> Find the Exact value
stiv31 [10]

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Step-by-step explanation:

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If u=arcsin(0.4), then sin(u)=0.4

By the Pythagorean Identity, cos^2(u)+sin^2(u)=1, we have cos^2(u)=1-sin^2(u)=1-(0.4)^2=1-0.16=0.84.

This also implies cos(u)=sqrt(0.84) since cosine is positive.

Plug in values:

tan(2u)=[2(0.4)(sqrt(0.84)]/[0.84-0.16]

tan(2u)=[2(0.4)(sqrt(0.84)]/[0.68]

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tan(2u)=[(40)(sqrt(0.84)]/[34]

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The answer is 48 km/hr
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