Question

What is the slope of the line that contains the points (2, -6) and (-3, 1)?

Answer 1

For this case we have that by definition, the slope of a line is given by:

$m = \frac {y2-y1} {x2-x1}$

We have to:

$(x1, y1) = (2, -6)\\(x2, y2) = (- 3,1)$

Substituting in the given expression we have:

$m = \frac {1 - (- 6)} {- 3-2}\\m = \frac {1 + 6} {- 3-2}\\m = \frac {7} {- 5}\\m = - \frac {7} {5}$

Answer:

$m = - \frac {7} {5}$

Answer 2

Answer:

The slope is $m=-\frac{7}{5}$

Step-by-step explanation:

The slope of the line passing through $(x_1,y_1)$ and $(x_2,y_2)$ is given by the formula;

$m=\frac{y_2-y_1}{x_2-x_1}$

The given line contains;the points (2, -6) and (-3, 1).

$m=\frac{1--6}{-3-2}$

$m=\frac{1+6}{-3-2}$

$m=\frac{7}{-5}$

The slope is $m=-\frac{7}{5}$