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USPshnik [31]
3 years ago
6

jorge was tracking the decreasing temperature in the morning. at 7 a.m. it was 65 degrees fahrenheit. at 9 a.m. it was 55 degree

s fahrenheit. If Jorge made the function f(x) = −5x + 100, what would the −5 represent? The temperature at midnight The length of time he recorded for The total change in degrees The rate at which the temperature was decreasing ??? help please
Mathematics
1 answer:
antiseptic1488 [7]3 years ago
6 0
<span>if at 7 it was 65 and at 9 it was 55, that means temperature is decreasing by 5 per hour</span>
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How to find two fractions between 1/2 and 1/3
raketka [301]
1. write 1/2 and 1/3 as fractions with a common denominator.

the common denominator must be a multiple of both 2 and 3, for example 6, 12, 24 etc... 

let the common denominator be 24

(1/2)(12/12)=12/24

(1/3)(8/8)=8/24

2. so , 9/24, 10/24, 11/24 are all fractions between 1/2 and 1/3



 
4 0
3 years ago
The equation for the line of best fit is y=2x+2.5. Soon, Edmond is going to a new fair. Use the equation for the line of best fi
andriy [413]

Answer:

x = 5

Step-by-step explanation:

The equation of a line is given by :

y=2x+2.5

Where

y is cost and x is number of tickets

Put y = $12.5 in the above equation

So,

12.5=2x+2.5

10 = 2x

x = 5

So, he can purchase 5 tickets.

4 0
2 years ago
Twenty-five percent of what number is 80?
tankabanditka [31]
The answer is 20
Hope this helps
3 0
2 years ago
Read 2 more answers
The number is odd.
77julia77 [94]

Answer:

Wow thats pretty hard the only things i could guess was the first one could be 18+ 18=36 and then there 6X6=36. but neither of those are greater than 50. And both of them are less than 75.

Step-by-step explanation:

Is this for a class??

7 0
3 years ago
EXAMPLE 5 Find the maximum value of the function f(x, y, z) = x + 2y + 11z on the curve of intersection of the plane x − y + z =
Taya2010 [7]

Answer:

\displaystyle x= -\frac{10}{\sqrt{269}}\\\\\displaystyle y= \frac{13}{\sqrt{269}}\\\\\displaystyle z = \frac{23\sqrt{269}+269}{269}

<em>Maximum value of f=2.41</em>

Step-by-step explanation:

<u>Lagrange Multipliers</u>

It's a method to optimize (maximize or minimize) functions of more than one variable subject to equality restrictions.

Given a function of three variables f(x,y,z) and a restriction in the form of an equality g(x,y,z)=0, then we are interested in finding the values of x,y,z where both gradients are parallel, i.e.

\bigtriangledown  f=\lambda \bigtriangledown  g

for some scalar \lambda called the Lagrange multiplier.

For more than one restriction, say g(x,y,z)=0 and h(x,y,z)=0, the Lagrange condition is

\bigtriangledown  f=\lambda \bigtriangledown  g+\mu \bigtriangledown  h

The gradient of f is

\bigtriangledown  f=

Considering each variable as independent we have three equations right from the Lagrange condition, plus one for each restriction, to form a 5x5 system of equations in x,y,z,\lambda,\mu.

We have

f(x, y, z) = x + 2y + 11z\\g(x, y, z) = x - y + z -1=0\\h(x, y, z) = x^2 + y^2 -1= 0

Let's compute the partial derivatives

f_x=1\ ,f_y=2\ ,f_z=11\ \\g_x=1\ ,g_y=-1\ ,g_z=1\\h_x=2x\ ,h_y=2y\ ,h_z=0

The Lagrange condition leads to

1=\lambda (1)+\mu (2x)\\2=\lambda (-1)+\mu (2y)\\11=\lambda (1)+\mu (0)

Operating and simplifying

1=\lambda+2x\mu\\2=-\lambda +2y\mu \\\lambda=11

Replacing the value of \lambda in the two first equations, we get

1=11+2x\mu\\2=-11 +2y\mu

From the first equation

\displaystyle 2\mu=\frac{-10}{x}

Replacing into the second

\displaystyle 13=y\frac{-10}{x}

Or, equivalently

13x=-10y

Squaring

169x^2=100y^2

To solve, we use the restriction h

x^2 + y^2 = 1

Multiplying by 100

100x^2 + 100y^2 = 100

Replacing the above condition

100x^2 + 169x^2 = 100

Solving for x

\displaystyle x=\pm \frac{10}{\sqrt{269}}

We compute the values of y by solving

13x=-10y

\displaystyle y=-\frac{13x}{10}

For

\displaystyle x= \frac{10}{\sqrt{269}}

\displaystyle y= -\frac{13}{\sqrt{269}}

And for

\displaystyle x= -\frac{10}{\sqrt{269}}

\displaystyle y= \frac{13}{\sqrt{269}}

Finally, we get z using the other restriction

x - y + z = 1

Or:

z = 1-x+y

The first solution yields to

\displaystyle z = 1-\frac{10}{\sqrt{269}}-\frac{13}{\sqrt{269}}

\displaystyle z = \frac{-23\sqrt{269}+269}{269}

And the second solution gives us

\displaystyle z = 1+\frac{10}{\sqrt{269}}+\frac{13}{\sqrt{269}}

\displaystyle z = \frac{23\sqrt{269}+269}{269}

Complete first solution:

\displaystyle x= \frac{10}{\sqrt{269}}\\\\\displaystyle y= -\frac{13}{\sqrt{269}}\\\\\displaystyle z = \frac{-23\sqrt{269}+269}{269}

Replacing into f, we get

f(x,y,z)=-0.4

Complete second solution:

\displaystyle x= -\frac{10}{\sqrt{269}}\\\\\displaystyle y= \frac{13}{\sqrt{269}}\\\\\displaystyle z = \frac{23\sqrt{269}+269}{269}

Replacing into f, we get

f(x,y,z)=2.4

The second solution maximizes f to 2.4

5 0
3 years ago
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